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3 years ago

What are the units of k in the following expression: rate = k [A][B]?

1 answer:

7 0

The units for k need to cancel when multiplied by [A][B] to leave the units for rate which should be M·s^-1

(M^-1 ·s^-1)*(M)*(M) = M·s^-1

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A 1.00 g sample of octane (C8H18) is burned in a bomb calorimeter with a heat capacity of 837J∘C that holds 1200. g of water at

lubasha [3.4K]

Answer:

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

Explanation:

Step 1: Data given

Mass of octane = 1.00 grams

Heat capacity of calorimeter = 837 J/°C

Mass of water = 1200 grams

Temperature of water = 25.0°C

Final temperature : 33.2 °C

Step 2: Calculate heat absorbed by the calorimeter

q = c*ΔT

⇒ with c = the heat capacity of the calorimeter = 837 J/°C

⇒ with ΔT = The change of temperature = T2 - T1 = 33.2 - 25.0 : 8.2 °C

q = 837 * 8.2 = 6863.4 J

Step 3: Calculate heat absorbed by the water

q = m*c*ΔT

⇒ m = the mass of the water = 1200 grams

⇒ c = the specific heat of water = 4.184 J/g°C

⇒ ΔT = The change in temperature = T2 - T1 = 33.2 - 25 = 8.2 °C

q = 1200 * 4.184 * 8.2 = 41170.56 J

Step 4: Calculate the total heat

qcalorimeter + qwater = 6863.4 + 41170. 56 = 48033.96 J = 48 kJ

Since this is an exothermic reaction, there is heat released. q is positive but ΔH is negative.

Step 5: Calculate moles of octane

Moles octane = 1.00 gram / 114.23 g/mol

Moles octane = 0.00875 moles

Step 6: Calculate heat combustion for 1.00 mol of octane

ΔH = -48 kJ / 0.00875 moles

ΔH = -5485.7 kJ/mol

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

8 0

3 years ago

This is the question i need help on

mash [69]

I thank that your answer is C.

8 0

4 years ago

The ideal gas law tends to become inaccurate when:

Maslowich

Answer:yes

Explanation:

4 0

3 years ago

Explain why hydrogen exhibits properties similar to those of both lithium and fluorine?

PtichkaEL [24]

Hydrogen exhibit similar properties with lithium because both are in the same group 1 as they both have a valence electron of 1

Hydrogen also exhibit some similar properties with fluorine simply because they are both non metals

<h3>What is an element?</h3>

An element is a substance which cannot be split into simpler forms by an ordinary chemical process. This simply goes to say that elements are substances which cannot be decomposed into simpler substances by ordinary chemical reactions.

An atom is the smallest unit or part of an element which can take part in a chemical reaction.

On a general note, elements are classified as thus:

Metals, non-metal, and metalloid.

The extreme left side elements in the periodic table are metals, for example, aluminum, sodium, calcium, caesium, etc.

However, elements on the right side are generally referred to as non-metals, carbon, chlorine, oxygen,

So therefore, hydrogen exhibit similar properties with lithium because both are in the same group 1 as they both have a valence electron of 1

Hydrogen also exhibit some similar properties with fluorine simply because they are both non metals

Learn more about atoms and elements:

brainly.com/question/6258301

#SPJ1

8 0

2 years ago

Balance the following reaction in KOH (under basic conditions). What are the coefficients in for C3H8O2 and KMnO4 in the balance

GrogVix [38]

Answer:

Coefficient of $C_3H_8O_2=3$

Coefficient of $KMnO_4$ =8

Explanation:

We are given that a reaction in which $C_3H_8O_2$ reacts with $KMnO_4$

We have to find the coefficient of each reactants in balanced reaction

$3C_3H_8O_2(aq)+8KMnO_4(aq)\rightarrow 3C_3H_2O_4K_2(aq)+8MnO_2(aq)+2KOH+8H_2O$

Coefficient is defined the constant value multiplied with a reactant in a reaction.

Coefficient of $C_3H_8O_2$ =3

Coefficient of $KMnO_4=8$

Coefficient of $C_3H_2O_4K_2=3$

Coefficient of $MnO_2=8$

Coefficient of $H_2O=8$

Coefficient of KOH=2

Hence, Coefficient of $C_3H_8O_2=3$ and coefficient of $KMnO_4=8$

7 0

3 years ago