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barxatty [35]
3 years ago
5

coach wants to make grilled cheese for her friends . she brings 5 different types of cheese and 3 different types of breads. how

many sandwiches can she make?
Mathematics
1 answer:
Virty [35]3 years ago
5 0

Answer:15 sandwiches

Step-by-step explanation: if you multiply 5 by 3 you get 15

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amm1812
The answer would be:

X = -1
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Use the pythagorean theorem to solve the problem. Round your answer to the nearest tenth if necessary.
lyudmila [28]
4^2 + b^2 = 12^2
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7 0
3 years ago
37. Construct Arguments Luis and Raul are
Katarina [22]

Using the slope - intercept relation, the required equation which models the scenario and Raul's speed are ;

  • <em>y</em><em> </em><em>=</em><em> </em><em>-</em><em> </em><em>7.5x</em><em> </em><em>+</em><em> </em><em>15</em><em> </em>
  • <em>4</em><em> </em><em>miles</em><em> </em><em>per</em><em> </em><em>hour</em><em> </em>

Time difference, Δt = 1.2 hours - 0.5 hours = 0.7 hours

Change in distance, Δd = 11.25 - 6 = 5.25 miles

Assuming a constant speed :

  • Speed = (Δd ÷ Δt) = (5.25 ÷ 0.7) = 7.5 mi/hr

<u>Using the general form</u> :

  • y = bx + c

At, x = 1.2 hours ;

Miles left, y = 6 miles

End point decreases by 7.5 mi/hr (-7.5 mi/hr)

Inputting the data into the equation :

6 = - 7.5(1.2) + c

6 = - 9 + c

c = 6 + 9 = 15 miles

<u>The expression in slope intercept form becomes</u> ;

  • y = -7.5x + 15

<u>If Raul lives 5 miles closer to the beach</u> ;

<u>Time it will take Luis to get to the beach</u> :

  • Time taken = (15 ÷ 7.5) = 2.5 hours

Distance Raul has to cover = 15 - 5 = 10 miles

To reach the beach after 2.5 hours ;

  • Speed required = (10 ÷ 2.5) = 4 mi/hr

Therefore, Raul has to ride at 4 miles per hour for the plan to work.

Learn more :brainly.com/question/18405415

5 0
2 years ago
5 days = ? hours <br> Can you please show work so i can understand better?
son4ous [18]
24 Hours in one Day

5 Days

24 <span>× 5 = 120 Hours


Hope that helps! </span>
8 0
3 years ago
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weqwewe [10]

Answer:

use dat brain

Step-by-step explanation:

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