Answer:
(C) 2P
Explanation:
Ideal gas law states:
PV = nRT
n (the number of moles) and R (ideal gas constant) are constant, so we can say:
(PV / T) before = (PV / T) after
Chamber X starts at pressure P, volume V, and temperature T. At equilibrium, the pressure is Px, the volume is Vx, and temperature 3T.
PV / T = Px Vx / 3T
Chamber Y starts at pressure P, volume V, and temperature T. At equilibrium, the pressure is Py, the volume is Vy, and temperature T.
PV / T = Py Vy / T
Substituting and simplifying:
Px Vx / 3T = Py Vy / T
Px Vx / 3 = Py Vy
Since the chambers are at equilibrium, Px = Py:
Vx / 3 = Vy
Vx = 3 Vy
The total volume is the same as before, so:
Vx + Vy = 2V
Substituting:
(3 Vy) + Vy = 2V
4 Vy = 2V
Vy = V / 2
Now if we substitute into our equation for chamber Y:
PV / T = Py (V/2) / T
PV = Py (V/2)
Py = 2P
The pressure in chamber Y (and chamber X) doubles at equilibrium.
Answer:
Explanation:
Heat required to warm the water from 20 degree to 51 degree
= mct
= 131 x 4150 x ( 51 - 20 )
= 16853150 J
Power of heating element
= v² /R
Heat generated in 31 min
= (v² / r ) x 31 x 60 = 16853150
r = (240 x 240 x 31 x 60) / 16853150
6.35 ohm
In this case heat required will change so time will also change
Heat required =
131 x 4150 x ( 100-51 )
= 26638850 J
If time required be t hour
Energy consumed
Power x time
= (v² / r ) x t x 60 = 26638850
t = 26638850 x 6.35 / (240 x 240 x 60 )
= 48.95 h
Heat required to evaporate water at 100 degree
= mass x latent heat
= 131 x 2260000
= 296060000 J
Total heat required
= 296060000 + 26638850 + 16853150
= 339552000 J
time required = 339552000 x 6.35 / (240 x 240 x 60 )
= 623.88 h .
Answer:
The illumination on the book before the lamp is moved is 9 times the illumination after the lamp is moved.
Explanation:
The distance of the book before the lamp is moved, ![d_{b} = 30 cm](https://tex.z-dn.net/?f=d_%7Bb%7D%20%3D%2030%20cm)
The distance of the book after the lamp is moved, ![d_{a} = 90 cm](https://tex.z-dn.net/?f=d_%7Ba%7D%20%3D%2090%20cm)
Illumination can be given by the formula, ![E = \frac{P}{4 \pi d^{2} }](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7BP%7D%7B4%20%5Cpi%20d%5E%7B2%7D%20%7D)
Illumination before the lamp is moved, ![E_{b} = \frac{P}{4 \pi d_{b} ^{2} }](https://tex.z-dn.net/?f=E_%7Bb%7D%20%3D%20%5Cfrac%7BP%7D%7B4%20%5Cpi%20d_%7Bb%7D%20%5E%7B2%7D%20%7D)
Illumination after the lamp is moved, ![E_{a} = \frac{P}{4 \pi d_{a} ^{2} }](https://tex.z-dn.net/?f=E_%7Ba%7D%20%3D%20%5Cfrac%7BP%7D%7B4%20%5Cpi%20d_%7Ba%7D%20%5E%7B2%7D%20%7D)
![\frac{E_{a}}{E_{b}} } = \frac{\frac{P}{4 \pi d_{a} ^{2} } }{\frac{P}{4 \pi d_{b} ^{2} } }](https://tex.z-dn.net/?f=%5Cfrac%7BE_%7Ba%7D%7D%7BE_%7Bb%7D%7D%20%7D%20%3D%20%5Cfrac%7B%5Cfrac%7BP%7D%7B4%20%5Cpi%20d_%7Ba%7D%20%5E%7B2%7D%20%7D%20%7D%7B%5Cfrac%7BP%7D%7B4%20%5Cpi%20d_%7Bb%7D%20%5E%7B2%7D%20%7D%20%7D)
![\frac{E_{a} }{E_{b} } = \frac{d_{b} ^{2} }{d_{a} ^{2}} \\\frac{E_{a} }{E_{b} } = \frac{30^{2} }{90 ^{2}}\\\frac{E_{a} }{E_{b} } =\frac{900 }{8100}\\\frac{E_{a} }{E_{b} } =\frac{1 }{9}](https://tex.z-dn.net/?f=%5Cfrac%7BE_%7Ba%7D%20%7D%7BE_%7Bb%7D%20%7D%20%3D%20%5Cfrac%7Bd_%7Bb%7D%20%5E%7B2%7D%20%7D%7Bd_%7Ba%7D%20%5E%7B2%7D%7D%20%5C%5C%5Cfrac%7BE_%7Ba%7D%20%7D%7BE_%7Bb%7D%20%7D%20%3D%20%5Cfrac%7B30%5E%7B2%7D%20%7D%7B90%20%5E%7B2%7D%7D%5C%5C%5Cfrac%7BE_%7Ba%7D%20%7D%7BE_%7Bb%7D%20%7D%20%3D%5Cfrac%7B900%20%7D%7B8100%7D%5C%5C%5Cfrac%7BE_%7Ba%7D%20%7D%7BE_%7Bb%7D%20%7D%20%3D%5Cfrac%7B1%20%7D%7B9%7D)
![E_{b} = 9E_{a}](https://tex.z-dn.net/?f=E_%7Bb%7D%20%3D%209E_%7Ba%7D)
The illumination on the book before the lamp is moved is 9 times the illumination after the lamp is moved.
Answer:
When a ball thrown upward reaches its highest point, its velocity is? is still -9.8 m/s2. The acceleration due to gravity is always -9.8 m/s/s, regardless of the ball's velocity.