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Serga [27]
3 years ago
11

Name 5 types of energy​

Chemistry
2 answers:
Helen [10]3 years ago
3 0
Mechanic energy electrical energy. light energy thermal energy. sound energy
Blababa [14]3 years ago
3 0

Answer:

Mechanical electric thermal chemical nuclear sound light

Explanation:

a simple abbreviation is M.E.L.T.S C.N

THESE ARE THE BASIC FORMS NOT ALL

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Why are large differences in temperature between the wet bulb and dry bulb thermometers are possible only at higher temperatures
photoshop1234 [79]

Answer:

At constant vapor pressure, the relative humidity decreases as the temperature increases, therefore, at higher temperature the relative humidity is low and water readily evaporates from the wet bulb thermometer that results in the cooling of the bulb such that at a given ambient temperature the very low relative humidity results in very large differences between the temperatures of the wet bulb thermometer and that of the dry bulb thermometer and the wet bulb is observed to be the colder thermometer of the two

Explanation:

8 0
3 years ago
"46.7 g of water at 80.6 oC is added to a calorimeter that contains 45.33 g of water at 40.6 oC. If the final temperature of the
soldier1979 [14.2K]

<u>Answer:</u> The specific heat of calorimeter is 30.68 J/g°C

<u>Explanation:</u>

When hot water is added to the calorimeter, the amount of heat released by the hot water will be equal to the amount of heat absorbed by cold water and calorimeter.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[(m_2\times c_2)+c_3](T_{final}-T_2)       ......(1)

where,

q = heat absorbed or released

m_1 = mass of hot water = 46.7 g

m_2 = mass of cold water = 45.33 g

T_{final} = final temperature = 59.4°C

T_1 = initial temperature of hot water = 80.6°C

T_2 = initial temperature of cold water = 40.6°C

c_1 = specific heat of hot water = 4.184 J/g°C

c_2 = specific heat of cold water = 4.184 J/g°C

c_3 = specific heat of calorimeter = ? J/g°C

Putting values in equation 1, we get:

46.7\times 4.184\times (59.4-80.6)=-[(45.33\times 4.184)+c_3](59.4-40.6)

c_3=30.68J/g^oC

Hence, the specific heat of calorimeter is 30.68 J/g°C

6 0
3 years ago
what mass of sulfur dioxide would be produced if 64 tonnes of sulfur was completely reacted with oxygen gas?
inysia [295]

Answer:

128tonnes

Explanation:

Check attachment  

7 0
4 years ago
If matter is uniform throughout and cannot be separated into other substances by physical processes, but can be decomposed into
elixir [45]

Answer:

Compound

Explanation:

A compound is a substance that cannot be broken down by an ordinary physical process but can be split into its component elements by chemical processes such as decomposition, dissociation, displacement.

A compound is made up of two or more different atoms. A particular compound is unique/uniform in its composition and doesn't share its particular composition with another compound. For example, carbon monoxide (CO) is made up of one atom of carbon and one atom of oxygen while carbon dioxide (CO₂) is made up of one atom of carbon and two atoms of oxygen.

5 0
3 years ago
Given that the density of water is 0.975 g/mL and that 171 g of sucrose (molar mass: 342.30 g/mol) is dissolved in 512.85 mL of
nikitadnepr [17]
1.00 m is the molality of this solution
7 0
3 years ago
Read 2 more answers
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