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3 years ago

Determine the empirical formula of a

Chemistry

1 answer:

k0ka [10]3 years ago

3 0

Answer:

AuCl

Explanation:

Given parameters:

Mass of Gold = 2.6444g

Mass of Chlorine = 0.476g

Unknown:

Empirical formula = ?

Solution:

Empirical formula is the simplest formula of a compound. Here is the way of determining this formula.

Elements Au Cl

Mass 2.6444 0.476

Molar mass 197 35.5

Number of moles 2.6444/197 0.476/35.5

0.013 0.013

Divide by the

smallest 0.013/0.013 0.013/0.013

1 1

The empirical formula of the compound is AuCl

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The mass percentage of hydrochloric acid within a solution is 28.00%28.00% . Given that the density of this solution is 1.1411.1

sashaice [31]

Answer:

8.76M

Explanation:

Given that

Mass from the density = 1141g

According to the given situation the computation of molarity of the solution is shown below:-

we will took HCL solution which is 1000mL

HCl = 28% by mass

So,

Mass of HCl in 1-litre solution is

$= \frac{28}{100} \times 1141$

Which gives the result of molar mass HCI is

= 319.48g /mol

Now,

Molarity is

$= \frac{319.48}{36.45}$

Which gives results of molarity is

= 8.76M

8 0

3 years ago

Consider the following mechanism for the reaction between nitric oxide and ozone:

swat32

Answer:

A . 2 O₃(g) + 2 NO ⇒ 2 O₂ (g) + 2 NO₂(g)

B . Yes

C. O and NO₃

Explanation:

A. The overall reaction is obtained by adding the individual steps in the reaction mechanism where we will get the reactants and product and the intermediates will cancel.

Thus, adding 1+ 2 +3 we get

2 O₃(g) + 2 NO ⇒ 2 O₂ (g) + 2 NO₂(g)

B. The reaction intermediates are those that are produced from the initial and/or subsequent steps and are consumed later on in the reaction mechanism, but are neither reactants nor products, they just participate.

From this definition it follows that O(g) and NO₃ are reaction intermediates.

C. O and NO₃

6 0

3 years ago

This image shows the development of what climate phenomenon?

Tpy6a [65]

Answer:

Rain shadow

Explanation:

Climate is the average weather condition of a place over a long period of time.

The image shows a rain shadow effect around a mountainous region. The type of rainfall controlled this way is known as an orographic rainfall.

On the leeward side which is the opposite side of where the rain cloud forms, there is dryness and lack of rainfall.
As moist air rises along the edge of the windward side, cloud forms.
This windward side receives a significant amount of rainfall
The windward side is hit with cold and dry wind and it is barren.

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3 years ago

One way of obtaining pure sodium carbonate is through the decomposition of the mineral trona, Na3(CO3)(HCO3)·2H2O. 2Na3(CO3)(HCO

zhenek [66]

Percentage yield = (actual yield / theoretical yield) x 100%

The balanced equation for the decomposition is,
2Na₃(CO₃)(HCO₃)·2H₂O(s) → 3Na₂CO₃(s) + CO₂(g) + 5H₂<span>O(g)

The stoichiometric ratio between </span>Na₃(CO₃)(HCO₃)·2H₂O(s) and Na₂CO₃(s) is 2 : 3

The decomposed mass of Na₃(CO₃)(HCO₃)·2H₂O(s) = 1000 kg
= 1000 x 10³ g

Molar mass of Na₃(CO₃)(HCO₃)·2H₂O(s) = 226 g mol⁻¹
moles of Na₃(CO₃)(HCO₃)·2H₂O(s) = mass / molar mass
= 1000 x 10³ g / 226 g mol⁻¹
= 4424.78 mol

Hence, moles of Na₂CO₃ formed = 4424.78 mol x $\frac{3}{2}$
= 6637.17 mol

Molar mass of Na₂CO₃ = 106 g mol⁻¹

Hence, mass of Na₂CO₃ = 6637.17 mol x 106 g mol⁻¹
= 703540.02 g
= 703.540 kg

Hence, the theoretical yield of Na₂CO₃ = 703.540 kg
Actual yield of Na₂CO₃ = 650 kg

Percentage yield = (650 kg / 703.540 kg) x 100%
= 92.34%

7 0

3 years ago

With no difference in temperatures and 100% humidity, will it rain? Why or Why not?

Artyom0805 [142]

Not necessarily, rain needs some mechanism such as instability of vertical air movement..

7 0

3 years ago