Here, Fe = Fg
q.E = m.g
We have: E = 360 V
m = 5.4 × 10⁻⁵
g = 9.8 m/s² [ constant value for earth system ]
Substitute their values into the expression:
q (360) = 5.4 × 10⁻⁵ × 9.8
q = 52.92 × 10⁻⁵ / 360
q = -1.47 × 10⁻⁶ [ negative sign represents the nature of charge ]
So, Your Final answer would be 1.47 × 10⁻⁶
Hope this helps!
Answer:
1) 460.5 N
2) 431.7 N
Explanation:
Draw a free body diagram. There are four forces on the hammer:
Applied force 62.5 N in the +x direction, 30 cm from the ground
Reaction force Rᵧ in the +y direction, at the point of contact
Reaction force Rₓ in the +x direction, at the point of contact
Reaction force F at 31° from the vertical, 4.75 cm to the left of the point of contact
Part One
To find F, sum the moments about the point of contact:
∑τ = Iα
(62.5 N) (30 cm) − (F cos 31°) (4.75 cm) = 0
F = 460.5 N
Part Two
To find Rₓ and Rᵧ, sum the forces in the x and y directions.
∑Fₓ = ma
62.5 N − F sin 31° + Rₓ = 0
Rₓ = 174.7 N
∑Fᵧ = ma
-F cos 31° + Rᵧ = 0
Rᵧ = 394.7 N
The net reaction force at the point of contact is:
R = √(Rₓ² + Rᵧ²)
R = 431.7 N
The vertical forces add up to zero.
The net force on the object is 60N to the right.
F = m • a
60N right = (10kg) • (a)
a = (60N right) / (10kg)
a = 6 m/s^2 to the right
Multi-engine Commercial would be nice.
Maybe, but she hasn't proved it yet. As another example, somebody may bring a jar of gas to your laboratory, and you test the gas in the jar and you find nitrogen atoms, oxygen atoms, argon atoms, and krypton atoms, and there isn't a single compound in it. The gas in the jar is a MIXTURE of gases . . . a mixture that we call "Air".
