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Dennis_Churaev [7]
3 years ago
5

Which of these statements articulate one of Kirchhoff's laws? (Select all that apply)

Physics
1 answer:
aleksley [76]3 years ago
8 0

Answer: E) and F)

Explanation:

E) In any closed loop, the sum of all voltage drops must be zero, as it is stated in the Kirchhoff Voltage Law (KVL).

This is a direct consequence of the energy conservation principle, as if it could be possible to return to the starting point in a loop with a different voltage, this energy could be used as a infinite energy source, which is against laws of nature, specially Thermodynamic's 2nd law.

F) At any junction, the sum of the currents into it, must be equal to the sum of the currents that leave the junction, as it is stated in the Kirchhoff"s Current Law (KCL).

This is a direct consequence of the charge conservation principle, as the charge can't  neither  be accumulated nor be destroyed at any point.

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A magnetic field of 37.2 t has been achieved at the mit francis bitter national magnetic laboratory. Find the current needed to
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Answer:

Here is the complete question:

https://www.chegg.com/homework-help/questions-and-answers/magnetic-field-372-t-achieved-mit-francis-bitter-national-magnetic-laboratory-find-current-q900632

a) Current for long straight wire  =3.7\ MA

b) Current at the center of the circular coil =2.48\times 10^{5}\ A

c) Current near the center of a solenoid 236.8\ A

Explanation:

⇒ Magnetic Field due to long straight wire is given by (B),where B=\frac{\mu\times I}{2\pi(r) },so\ I=\frac{B\ 2\pi(r)}{\mu}

\mu=4\pi \times 10^{-7}\ \frac{henry}{m}

Plugging the values,

Conversion 1\times 10^6 A = 1\ MA,and 2cm=\frac{2}{100}=0.02\ m

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⇒Magnetic Field at the center due to circular coil (at center) is given by,B=\frac{\mu\times I (N)}{2(a)}

So I= \frac{2B(a)}{\mu\ N} = \frac{2\times 37.2\times 0.42}{4\pi\times 10^{-7}\times 100}=2.48\time 10{^5}\ A

⇒Magnetic field due to the long solenoid,B=\mu\ nI=\mu (\frac{N}{l})I

Then I=\frac{B}{\mu(\frac{N}{L})} \approx 236.8\A  

So the value of current are  3.7 MA,2.48\times 10^{5} A and 236.8\ A respectively.

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