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Murljashka [212]
3 years ago
14

A horizontal rope is tied to a 58.0 kg box on frictionless ice. what is the tension in the rope the box is at rest

Physics
1 answer:
alexandr402 [8]3 years ago
3 0
48kg is the tension in the rope
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a golfer is on the edge of a 12.5m bluff overlooking the 18th hole which is located 67.1m from the base of the bluff. she launch
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Answer: 26.359 m/s

Explanation:

This problem is related to parabolic motion and can be solved by the following equations:

x=V_{o}cos \theta t (1)

y=y_{o}+V_{o} sin \theta t - \frac{1}{2}gt^{2} (2)

V=V_{o}-gt (3)

Where:

x=67.1 m is the horizontal distance traveled by the golf ball

V_{o} is the golf ball's initial velocity

\theta=0\° is the angle (it was  a horizontal shot)

t is the time

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y_{o}=12.5 m is the initial height of the ball

g=9.8 m/s^{2} is the acceleration due gravity

V is the final velocity of the ball

Let's begin by finding t  from (2):

t=\sqrt{\frac{2 y_{o}}{g}} (4)

t=\sqrt{\frac{2 (12.5 m)}{9.8 m/s^{2}}} (5)

t=1.597 s (6)

Substituting (6) in (1):

67.1 m=V_{o} cos(0\°) 1.597 s (7)

Finding V_{o}:

V_{o}=42.01 m/s (8)

Substituting V_{o} in (3):

V=42.01 m/s-(9.8 m/s^{2})(1.597 s) (9)

Finally:

V=26.359 m/s

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~{Dunsforhands}</span>
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