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3 years ago

An alternating current is set up in an LRC circuit.

Physics

1 answer:

Andreyy893 years ago

7 0

Answer:

(B) Resistor only

Explanation:

Alternating Current: These are currents that changes periodically with time.

An LRC Ac circuit is an AC circuit that contains a Resistor, a capacitor and an inductor, connected in series.

In a purely resistive circuit, current and voltage are in phase.

In a purely capacitive circuit, the current leads the voltage by π/2

In a purely inductive circuit, the current lags the voltage by π/2.

Therefore when a alternating current is set up in LRC circuit, in the resistor, the current and the voltage are in phase.

The right option is (B) Resistor only.

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A racing car’s velocity is increased from 44 m/s to 66 m/s in 11 seconds. What is the acceleration? and what is the displacement

Musya8 [376]

Answer:

Explanation:

Acceleration is defined as the change in velocity per unit of time

Acceleration (a) = ΔV/t

V = Velocity t = time

ΔV = V₂ - V₁ t = 11s

V₁ = 44m/s

V₂ = 66m/s

ΔV = 66 - 44

= 22m/s

Acceleration (a) = 22/11

= 2m/s²

Displacement (d): Displacement equals the original velocity multiplied by time plus one half the acceleration multiplied by the square of time.

d = v₀ + 1/2*at²

v₀ = 44m/s

a = 2m/s

t = 11s

d = 44 + 1/2*(2 x 11²)

= 44 + 121

d = 165m

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4 years ago

the imagine above shows to opposite forces acting on a rolling cart, what can we say is true about affect of the forces on the c

cluponka [151]

Answer:

Here is my answer...

Explanation:

The cart will connect with the opposite force, and then the cart will come to a shuddering stop before moving in the direction of the oposite force.

Hope I helped! :)

7 0

3 years ago

A fuse in an electric circuit is a wire that is designed to melt, and thereby open the circuit, if the current exceeds a predete

arlik [135]

Answer:

0.0389 cm

Explanation:

The current density in a conductive wire is given by

$J=\frac{I}{A}$

where

I is the current

A is the cross-sectional area of the wire

In this problem, we know that:

- The fuse melts when the current density reaches a value of

$J=520 A/cm^2$

- The maximum limit of the current in the wire must be

I = 0.62 A

Therefore, we can find the cross-sectional area that the wire should have:

$A=\frac{I}{J}=\frac{0.62}{520}=1.19\cdot 10^{-3} cm^2$

We know that the cross-sectional area can be written as

$A=\pi \frac{d^2}{4}$

where d is the diameter of the wire.

Re-arranging the equation, we find the diameter of the wire:

$d=\sqrt{\frac{4A}{\pi}}=\sqrt{\frac{4(1.19\cdot 10^{-3})}{\pi}}=0.0389 cm$

3 0

3 years ago

How are nuclear reactions used to meet the world’s energy needs?

N76 [4]

Answer: How are nuclear reactions used to meet the world's energy needs? Both fusion and fission are used to generate electricity, but more fission reactors than fusion reactors are in use. ... Both fusion and fission are used to generate electricity, but more fusion reactors than fission reactors are in use.

Explanation:

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4 years ago

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You need to use your cell phone, which broadcasts an 830 MHz signal, but you’re in an alley between two massive, radio- wave-abs

Korvikt [17]

Answer:Angular width of the electromagnetic wave after it emerges from between the buildings is 2.761 degree

Explanation:

The wavelength of the electromagnetic wave is

$\lambda=\frac{c}{f} \\\lambda=\frac{3\times 10^8}{830\times 10^6} \\\lambda=0.361 m$

Consider two buildings as a single slit, for single slit diffraction dark fringes are located an angle of

$\theta _{p}=sin^{-1}\frac{\lambda}{a}$

where $\lambda$ is frequency, $a$ is space between buildings.

For the first dark fringes

$\theta _{1}=sin^{-1}\frac{\lambda}{a}\\\theta _{1}=sin^{-1}\frac{0.3614}{15}\\\theta _{1}=1.38^{0}$

Angular width of the electromagnetic wave after it emerges from between the buildings is

$\Delta\theta =2\theta _{1}\\\Delta\theta =2\times 1.38\\\Delta\theta =2.761^0$

6 0

3 years ago