The oxidation number of elements in equation below are,
4NH₃ + 3Ca(ClO)₂ → 2N₂ + 6H₂O + 3CaCl₂
O.N of N in NH₃ = -3
O.N of Ca in Ca(ClO)₂ and CaCl₂ = +2
O.N of N in N₂ = 0
O.N of Cl in Ca(ClO)₂ = +1
O.N of Cl in CaCl₂ = -1
Oxidation:
Oxidation number of Nitrogen is increasing from -3 (NH₃) to 0 (N₂).
Reduction:
Oxidation number of Cl is decreasing from +1 [Ca(ClO)₂] to -1 (CaCl₂).
Result:
<span>N is oxidized and Cl is reduced.</span>
Answer:
D atom
Explanation:
The smallest particle of a substance that retains the chemical and physical properties of the substance and is composed of two or more atoms
Answer: The empirical formula for the given compound is 
Explanation : Given,
Percentage of H = 18 %
Percentage of N = 82 %
Let the mass of compound be 100 g. So, percentages given are taken as mass.
Mass of H = 18 g
Mass of N = 82 g
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Hydrogen = 
Moles of Nitrogen = 
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 5.8 moles.
For Hydrogen = 
For Nitrogen = 
Step 3: Taking the mole ratio as their subscripts.
The ratio of H : N = 3 : 1
Hence, the empirical formula for the given compound is 
Answer:
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Explanation:
If nutrients are added to an ecosystem, then the composition of the plant community at different stages of succession will also change because different species take advantage of different soil conditions.
Answer: Hello your question lacks some details below is the complete question
answer :
Numerator = CH₃OH
Denominator = (CO ) ( H₂)²
Explanation:
CO + 2H₂ ⇄ CH₃OH ( formation of methanol )
hence for the equilibrium constant Kc
Numerator = CH₃OH
Denominator = (CO ) ( H₂)²
<u><em>Placing into the Bin </em></u>
Numerator : CH₃OH
Denominator : (CO ) ( H₂)²
Not Used : ( CO )² , H₂ , ( CH₃OH ) ²