The molecular formula of HgCl (m = 5 472.1 g/mol) is Hg2Cl4.
The molecular formula is an expression that defines the number of atoms of each element in one molecule of a compound. It shows the actual number of each atom in a molecule.
<h3>Molecular formula: What is it?</h3>
A chemical formula is a way to communicate information in chemistry about the proportions of atoms that make up a specific chemical compound or molecule. Chemical element symbols, numbers, and occasionally other symbols like parentheses, dashes, brackets, commas, and plus and minus signs are used to represent the chemical elements.
A molecule's molecular formula reveals which atoms and how many of each kind are included within it. No subscript is used if there is just one atom of a certain kind. A subscript is added to the symbol for an atom if it contains two or more of a certain type of atom.
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Answer: Avogrado's Constant
Explanation:
One mole of a substance is equal to 6.022 × 10²³ units of that substance (such as atoms, molecules, or ions). The number 6.022 × 10²³ is known as Avogadro's number or Avogadro's constant. The concept of the mole can be used to convert between mass and number of particles.
Yes, because CO2 is carbon dioxide, and carbon dioxide contains molecules.
Once the student has finished his experiment, additional steps he may take are to analyze the data gathered and draw a conclusion, then publish his findings to be seen by his peers (other students).
<h3 /><h3>What comes after the experiment?</h3>
- Once an experiment is concluded, one must go over the data gathered.
- By this, we mean to analyze the information obtained through the experiment.
- This allows the student to draw a conclusion backed by evidence.
- Once complete, it is wise to share and discuss the findings with peers.
Therefore, we can confirm that once the experiment is completed, the most common action that follows is to draw a conclusion based on the analysis of the data gathered during the experiment, then discuss the findings with peers.
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Answer:
Explanation:
Here we have to use stoichiometry.
First of all, we have to calculate the mass of 100% of yield:
1.7 g ------- 98%
X -------- 100%
X = 1.73 g (approximately)
Second, we have to calculate the mass of N2 that is necessary to react to produce the mass of 1.73g of NH3. To do that, we have to use the Molar mass of N2 and NH3 and don't forget the stoichiometric relationship between them.
Molar Mass N2 : 14x2 = 28 g/mol
Molar Mass NH3: 14 + 3 = 17 g/mol
28g (N2) ------- 17x2 (NH3)
X ------------ 1.73 g
X = 1.42 g (approximately)
