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Nutka1998 [239]
3 years ago
12

Sawzall® is another term commonly applied to?

Engineering
1 answer:
Virty [35]3 years ago
8 0

Answer:

reciprocating saw

Explanation:

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Guys do u know who is
avanturin [10]
I think so, I’ve seen her on here a couple of times. Though I’ve never spoken with said person

Hope this helps you (also why?)
6 0
4 years ago
Read 2 more answers
A force is specified by the vector F= 160i + 80j + 120k N. Calculate the angles made by F with the positive x-, y-, and z-axis.
Rashid [163]

Answer:

1) Angle with x-axis = 42.03 degrees

2) Angle with y-axis =68.2 degrees

3) Angle with z-axis =   56.14 degrees

Explanation:

given any vector \overrightarrow{r}=x\widehat{i}+y\widehat{j}+z\widehat{k}

and any x axis the angle between them is given by

\theta_x =cos^{-1}(\frac{\overrightarrow{r}\cdot\widehat{i}}{\sqrt{x^2+y^2+z^2}} )\\\\\theta_x=cos^{-1}(\frac{x\cdot i}{\sqrt{x^2+y^2+z^2}} )

Applying values we get

\theta_x=cos^{-1}(\frac{160}{\sqrt{160^2+80^2+120^2}} )=42.03^{o}

Angle between the vector and y axis is given by

\theta_y =cos^{-1}(\frac{\overrightarrow{r}\cdot\widehat{j}}{\sqrt{x^2+y^2+z^2}} )\\\\\theta_y=cos^{-1}(\frac{y\cdot j}{\sqrt{x^2+y^2+z^2}} )

Applying values we get

\theta_x=cos^{-1}(\frac{80}{\sqrt{160^2+80^2+120^2}} )=68.2^{o}

Similarly angle between z axis and the vector is given by

\theta_z =cos^{-1}(\frac{\overrightarrow{r}\cdot\widehat{k}}{\sqrt{x^2+y^2+z^2}} )\\\\\theta_x=cos^{-1}(\frac{z\cdot k}{\sqrt{x^2+y^2+z^2}} )

Applying values we get

\theta_z=cos^{-1}(\frac{120}{\sqrt{160^2+80^2+120^2}} )=56.145^{o}

5 0
4 years ago
A worker's hammer is accidentally dropped from the 20th floor of a building under construction. With what velocity does it strik
Illusion [34]

Answer:

Final Velocity (Vf)= 139.864 ft/s

Time (t)= 4,34 s

Explanation:

This is a free fall problem, to solve it we will apply free  fall concepts:

In a free fall the acceletarion is gravity (g) = 9,81 m/s2, if we convert it to ft/s^2 = g= 32.174 ft/s^2

  • Final velocity is Vf= Vo+ g*t[tex]Vf^{2} = Vo^{2} +2*g*h

where h is height (304 ft in this case).

Vo =0 since the hammer wasn't moving when it stared to fall

Then Vf^2= 0 + 2* 32.174 ft/s^2 *304 ft

          Vf^2= 19,561.8224  ft^2/s^2

          Vf=[sqrt{19561.8224 ft^2/s^2}

          Vf=139.864 ft/s

Time t= (Vf-Vo)/g => (139.864 ft/s-0)/32.174 ft/s^2 = 4.34 sec

Good luck!

8 0
3 years ago
There are 22 people in the classroom 12 are we
Leni [432]
22 because all should wear safety glasses to be protected
6 0
3 years ago
Read 2 more answers
What are the four categories of engineering materials used in manufacturing?
alexgriva [62]

Answer:

metals, composite, ceramics and polymers.

Explanation:

The four categories of engineering materials used in manufacturing are metals, composite, ceramics and polymers.

i) Metals: Metals are solids made up of atoms held by matrix of electrons. They are good conductors of heat and electricity, ductile and strong.

ii) Composite: This is a combination of two or more materials. They have high strength to weight ratio, stiff, low conductivity. E.g are wood, concrete.

iii) Ceramics: They are inorganic, non-metallic crystalline compounds with high hardness and strength as well as poor conductors of electricity and heat.

iv) Polymers: They  have low weight and are poor conductors of electricity and heat

8 0
3 years ago
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