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Nutka1998 [239]
3 years ago
12

Sawzall® is another term commonly applied to?

Engineering
1 answer:
Virty [35]3 years ago
8 0

Answer:

reciprocating saw

Explanation:

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Which of the following applies to a module?
Ipatiy [6.2K]

Answer:

D all of the above

Explanation:

because I said so

3 0
2 years ago
Supercharging is the process of (a) Supplying the intake of an engine with air at a density greater than the density of the surr
iVinArrow [24]

Answer:

a)supplying the  intake of an engine  with air at a  density greater  than the density  of the surrounding  atmosphere

Explanation:

Supercharging  is the process of  supplying the  intake of an engine  with air at a  density greater  than the density  of the surrounding  atmosphere.

By doing this , it increases  the power out put  and increases the  brake thermal  efficiency of the  engine.It also  increases the  volumetric efficiency of the  engine.

So the our  option a is  right.

4 0
3 years ago
Suppose the country of Bangladesh wants a low interest loan to invest in the building of infrastructure. Which international org
musickatia [10]

Answer:

C. UNDP or World Bank.

Explanation:

Suppose the country of Bangladesh wants a low interest loan to invest in the building of infrastructure. The international organizations which Bangladesh would most likely turn to are UNDP or World Bank.

3 0
3 years ago
A 650-kN column load is supported on a 1.5 m square, 0.5 m deep spread footing. The soil below is a well-graded, normally consol
insens350 [35]

<u>Explanation:</u>

Determine the weight of footing

W_{f}=\gamma(L)(B)(D)

Where W_{f} is the weight of footing, γ is the unit weight of concrete,  L is the length of footing is the width of footing, and D is the depth of footing

Substitute 2 m \text { for } L, 1.5 m \text { for } B, 0.5 m \text { for } D \text { and } 23.6 kN / m ^{3} for γ in the equation

\begin{aligned}W_{f} &=\left(23.6 kN / m ^{3}\right)(2 m )(1.5 m )(0.5 m ) \\&=35.4 kN\end{aligned}

Therefore, the weight of the footing is 35.4 kN

Determine the initial vertical effective stress.

\sigma_{z p}^{\prime}=\gamma(D+B)-u

Here,   \sigma_{z^{p}}^{\prime} is initial vertical stress at a depth below ground surface  γ is the unit weight of soil, D is depth and u is pore water pressure.

Substitute 18 kN / m ^{3} \text { for } \gamma, 1.5 m \text { for } B, 0.5 m \text { for } D \text { and } 0 for u in the equation

\begin{aligned}\sigma_{z p}^{\prime} &=\left(18 kN / m ^{3}\right)(1.5+0.5) m -0 \\&=36 kPa\end{aligned}

Therefore, the initial vertical stress is 36 kPa

Determine the vertical effective stress.

\sigma_{z D}^{\prime}=\gamma D

Here,   \sigma_{z^{p}}^{\prime} is initial vertical stress at a depth below ground surface  γ is the unit weight of soil, D is depth and u is pore water pressure.

Substitute \(18 kN / m ^{3}\) for \(\gamma, 0.5 m\) for \(D\) and 0 for \(u\) in the equation.

\begin{aligned}\sigma_{z b}^{\prime} &=\left(18 kN / m ^{3}\right)(0.5 m )-0 \\&=9 kPa\end{aligned}

Therefore, the vertical stress at a depth below the ground surface is

9 kPa

Determine the influence factor at the midpoint of soil layer,

I_{e p}=0.5+0.1 \sqrt{\frac{q-\sigma_{s 0}^{\prime}}{\sigma_{z p}^{\prime}}}

Here I_{e p} is the influence factor at the midpoint of soil layer  \sigma_{z^{p}}^{\prime} is initial vertical stress, \sigma_{z^{p}}^{\prime} is vertical effective stress, and Q is bearing pressure

Substitute 36 kPa for \(\sigma_{z p}^{\prime}, 228.47\) kPa for \(q,\) and 9 kPa for \(\sigma_{z D}^{\prime}\) in the equation\begin{aligned}I_{\epsilon P} &=0.5+0.1 \sqrt{\frac{228.47 kPa -9 kPa }{36 kPa }} \\&=0.75\end{aligned}

Therefore the influence factor at the midpoint of the soil layer is 0.693

6 0
3 years ago
5. Which of these materials in a shop contain metals and toxins and can pollute the environment? A) Antifreeze B) Solvents C) Ba
Elza [17]
As a multiple choice the only correct answer is D
3 0
3 years ago
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