Answer:
R = 35.27 Ohms
Explanation:
Given the following data;
Voltage = 230V
Power = 1500W
To find the resistance, R;
Power = V²/R
Where:
V is the voltage measured in volts.
R is the resistance measured in ohms.
Substituting into the equation, we have;
1500 = 230²/R
Cross-multiplying, we have;
1500R = 52900
R = 52900/1500
R = 35.27 Ohms.
Therefore, the resistance which the heating element needs to have is 35.27 Ohms.
Answer:
Explanation:
<u>Given Data:</u>
Radius = r = 40 m
Speed = v = 25 m/s
<u>Required:</u>
Centripetal Acceleration = 
= ?
<u>Formula:</u>
<u>Solution:</u>
![\sf a_{c} = \frac{v^2}{r} \\\\a_{c} = \frac{(25)^2}{40} \\\\a_{c} = \frac{625}{40} \\\\a_{c} = 15.6 m/s^2\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20a_%7Bc%7D%20%3D%20%5Cfrac%7Bv%5E2%7D%7Br%7D%20%5C%5C%5C%5Ca_%7Bc%7D%20%3D%20%5Cfrac%7B%2825%29%5E2%7D%7B40%7D%20%5C%5C%5C%5Ca_%7Bc%7D%20%3D%20%5Cfrac%7B625%7D%7B40%7D%20%5C%5C%5C%5Ca_%7Bc%7D%20%3D%2015.6%20m%2Fs%5E2%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
a = 1.666... m/s²
Explanation:
a = v2 - v1 / t2 - t1
a = 21m/s - 14m/s / 6s - 0s
a = 7m/s / 6s
a = 1.666... m/s²
I dint think energy can be used up because energy cant be created nor destroyed
Answer:
L = 5,955 m
Explanation:
For this exercise we must use the relation
R = ρ L / A
where R is the resistance that indicates that it is 1 Ω, the resistivity is taken from the tables ρ = 2.82 10⁻⁸ Ω m, L is the length of the wire and A is the cross section.
As it indicates to us in volume of aluminum to use we divide the two terms by the length
R / L = ρ L / (A L)
the volume of a body is its area times its length, therefore
R / L = ρ L / V
R = ρ L² / V
we clear the length of the wire
L = √ R V /ρ
we reduce the volume to SI units
v = 1 cm³ (1m / 10² cm)³ = 1 10⁻⁶ m
let's calculate
L = √ (1 1 10⁻⁶ / 2.82 10⁻⁸)
L = √ (0.3546 10²)
L = 5,955 m
