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solmaris [256]
3 years ago
8

Please help me thanks so much?!?!?.:;)))) I will mark you:))

Chemistry
2 answers:
Pepsi [2]3 years ago
6 0

Answer:

D)

Explanation:

bazaltina [42]3 years ago
5 0

Answer:

the last one

Explanation:

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Heyy pls help anyone?
madam [21]
1a. calcium chloride (CaCl2)
b. 2HCl (aq) + Ca(OH)2 (s) —> CaCl2 (aq) + 2H2O (l)

i’m not sure about the rest but i hope this helped ^^
7 0
3 years ago
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During the drying cycle, clothes soaked in liquid PERC at 300 K at 1 atm are tumbled in a stream of warm air at 330 K at 1 atm t
djyliett [7]
The answer is option A
6 0
3 years ago
Write the net ionic equation for the reaction of aqueous solutions of ammonium chloride and iron(III) hydroxide.
vagabundo [1.1K]

Answer:

Fe(OH)_3(s)\rightarrow Fe^{3+}(aq)+3OH^-(aq)

Explanation:

Hello.

In this case, for the reaction between aqueous solutions of ammonium chloride and iron (III) hydroxide, we have the following complete molecular reaction:

3NH_4Cl(aq)+Fe(OH)_3(s)\rightarrow 3NH_4OH+FeCl_3

And the full ionic equation, taking into account that the iron (III) hydroxide cannot be dissolved as it is insoluble in water:

3NH_4^+(aq)+3Cl^-(aq)+Fe(OH)_3(s)\rightarrow 3NH_4^+(aq)+3OH^-(aq)+Fe^{3+}(aq)+3Cl^-(aq)

Finally, the net ionic equation, considering that spectator ions are NH₄⁺, Cl⁻ as they are both the left and right side, therefore, the net ionic equation is:

Fe(OH)_3(s)\rightarrow Fe^{3+}(aq)+3OH^-(aq)

Best regards.

8 0
2 years ago
A sample of iron has the dimensions of 2 cm x 3 cm x 2 cm. If the mass of this
77julia77 [94]

Answer: Volume iron = 2 x 3 x 2 => 12 cm³

Mass = 94 g

D = m / V

D = 94 / 12

D = 7.833 g/cm³

Explanation:

5 0
3 years ago
Balance this equation and pick the answer with the coefficients that belong there.
geniusboy [140]

Answer:

2,3,6,1

2,3,6,1

Explanation:

The unbalanced reaction expression is given as:

  AlBr₃    +    K₂SO₄  →    KBr  + Al₂(SO₄)₃

We need to balanced this reaction equation. Our approach is a mathematical method where we assign variable a,b,c and d as the coefficients.

 aAlBr₃    +    bK₂SO₄  →    cKBr  + dAl₂(SO₄)₃

Conserving Al;  a  = 2d

                   Br:  3a  = c

                   K:   2b = c

                   S:   b  = 3d

                   O:  4b  = 12d

Let a  = 1, c = 3, d  = \frac{1}{2}  b  = \frac{3}{2}  

 Multiply through by 2 to give;

     a  = 2, b = 3, c = 6 and d  = 1

 2AlBr₃    +    3K₂SO₄  →    6KBr  + Al₂(SO₄)₃

6 0
2 years ago
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