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3 years ago

What is the number of grams of an element that is numerically equal to the atomic mass in amu?

1 answer:

3 0

The wording of your question doesn't quite make sense, but a mole of an element has the same mass in grams as a single atom of that element has in amu. The mole is defined as 6.02 x10^22 things, whether they be atoms or molecules or even moles! 6.02x10^22 atoms of carbon has a mass of 12.01 g, and a single atom of carbon has a mass of 12.01 amu. Hope this helps!

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How many moles of NH4NO3 are in 24 g of NH4NO3?

Virty [35]

Answer:

0.3 mole

Explanation:

number of moles grams

one 14+(4×1)+14+(3×16)

1 80

? 24

Therefore, 24×1÷80 = 0.3 moles of ammonium nitrate

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3 years ago

Of Be3+ , Li2+ , and He1+

Mama L [17]

Answer:He 1+

Explanation:

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3 years ago

Clayton pulled his back helping friend move and uses a thermal heat wrap to ease his muscle aches. How could Clayton monitor the

Marat540 [252]

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3 years ago

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Linolenic acid has cis double bonds with the formula ch3ch2ch=chch2ch=chch2ch=ch(ch2)7cooh. write out the abbreviated systematic

valentinak56 [21]

<span>Abbreviated systematic numbering for Linolenic Acid is,

18:3, n-3
Explanation:
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3 years ago

An object is located 51 millimeters from a diverging lens. The object has a height of 13 millimeters and the image height is 3.5

aleksandr82 [10.1K]

Answer:

B. 13.7 mm

Explanation:

by similarity of rectangular triangles, we have:

(1) Δ ABC and Δ AB'C'

∴ AB/AB' = AC/AC'

∴ hypotenuse (AB)² = AC² + BC².....Pythagorean theorem

⇒ AB² = (51 mm)² + (13 mm)²

⇒ AB² = 2770 mm²

⇒ AB = 52.63 mm

(2) Δ AB'C' :

∴ hypotenuse (AB')² = AC'² + B'C'²

∴ B'C' = 3.5 mm

from (1):

⇒ AB' = (AB)(AC') / AC = (52.63)(AC') / (51 mm)

⇒ AB' = 1.032AC'.......(3)

(3) in (2):

⇒ (1.032AC')² = AC'² + (3.5)²

⇒1.065AC'² = AC'² + 12.25

⇒ 0.065AC'² = 12.25

⇒ AC'² = 188.462

⇒ AC' = √188.462

⇒ AC' = 13.72 mm

8 0

3 years ago

Read 2 more answers