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3 years ago

A student wrote a chemical equation as shown.

Chemistry

1 answer:

borishaifa [10]3 years ago

6 0

Answer: The student must add 2 infront of both $H_2O$ and $SO_2$ to make the equation balanced.

Explanation:

A balanced chemical equation is one where all the individual atoms are equal on both sides of the reaction. It follows the law of conservation of mass.

For the given unbalanced chemical equation:

$2H_2S+3O_2\rightarrow H_2O+SO_2$

On the reactant side:

Atoms of H = 4

Atoms of S = 2

Atoms of O = 6

On the product side:

Atoms of H = 2

Atoms of S = 1

Atoms of O = 3

To balance the equation, a student must balance the atoms by adding 2 infront of both $H_2O$ and $SO_2$

For the balanced chemical equation:

$2H_2S+3O_2\rightarrow 2H_2O+2SO_2$

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How many moles of SO3 are in 2.4x10^24 molesculea of SO3

yawa3891 [41]

there are 4.0 moles of SO3

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3 years ago

Is the reaction mg²⁺(aq) + h₂o(l) → mgo(s) + 2h⁺(aq) endothermic or exothermic?

aliya0001 [1]

If energy is released, the reaction is exothermic. If energy is absorbed, the reaction is endothermic. Since heat is being absorbed in this reaction (to break down H2O into H2 and O), the reaction is endothermic.

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3 years ago

What temperature would 3.54 moles of xenon gas need to reach to exert a pressure of 1.57 atm at a volume of 34.6 l

ira [324]

Answer:

186.9Kelvin

Explanation:

The ideal gas law equation is PV = n R T

where

P is the pressure of the gas

V is the volume it occupies

n is the number of moles of gas present in the sample

R is the universal gas constant, equal to 0.0821 atm L /mol K

T is the absolute temperature of the gas

Ensure units of the volume, pressure, and temperature of the gas correspond to R ( the universal gas constant, equal to 0.0821 atm L /mol K )

n = 3.54moles

P= 1.57

V= 34.6

T=?

PV = n R T

PV/nR = T

1.57 x 34.6/3.54 x 0.0821

54.322/0.290634= 186.908620464= T

186.9Kelvin ( approximately to 1 decimal place)

5 0

3 years ago

What is the balanced NET ionic equation for the reaction when aqueous Cs₃PO₄ and aqueous AgNO₃ are mixed in solution to form sol

rusak2 [61]

Answer:

$PO_4^{3-}(aq)+3Ag^+(aq)\rightarrow Ag_3PO_4(s)$

Explanation:

Hello!

In this case, since the net ionic equation of a chemical reaction shows up the ionic species that result from the simplification of the spectator ions, which are those at both reactants and products sides, we take into account that aqueous species ionize into ions whereas liquid, solid and gas species remain unionized. In such a way, for the reaction of cesium phosphate and silver nitrate we can write the complete molecular equation:

$Cs_3PO_4(aq)+3AgNO_3(aq)\rightarrow Ag_3PO_4(s)+3CsNO_3(aq)$