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Vedmedyk [2.9K]
3 years ago
13

How many grams of CO2 are in 10 mol of the compound?

Chemistry
2 answers:
Rama09 [41]3 years ago
5 0
One mole of CO2 is the sum of all the compound's elements' molar masses
(C = 12.01g/mol; O = 16g/mol). That being said, one mole of CO2 is 12.01g + 16g + 16g which is equal to 44.01g. That being said, 10 mol of CO2 is 44.01g • 10 which is
440.1 grams
IrinaK [193]3 years ago
3 0
The answer is 60 grams.
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What is the empirical formula of a compound that is 24.42 % calcium, 17.07 % nitrogen, and 58.5% oxygen?
REY [17]

Answer:

CaN_{2} O_{6}

Explanation:

When calculating an empirical formula from percentages, assume you have a 100g sample. This allows you to convert the percentages directly to grams, because X % of 100g is X grams.

So:

24.42 % = 24.42 g Ca, 17.07% = 17.07g N, 58.5% = 58.5g O

The next step is to divide each mass by their molar mass to convert your grams to moles.

24.42/40.08 = 0.6092 mol

17.07/14.01 = 1.218 mol

58.85/15.99 = 3.680 mol

Then you will divide all of your mol values by the SMALLEST number of moles. This gives you whole numbers that are the mole ratio (subcripts) of the empircal formula.

0.6092 mol/0.6092 mol = 1

1.218 mol/0.6092 mol = 2

3.680 mol/0.6092 mol = 6

So the empirical formula is CaN_{2} O_{6}

5 0
3 years ago
50 points!! Brainliest if correct!!
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The answer is C. The answer is C because if u increase the surface area, the more reactants u will get. and if u get more The reactants will move faster. Hoped that Helped!:-)

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Answer:D

Explanation:

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