How does an atom differ from a molecule?
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Answer:
See below.
Step-by-step explanation:
Ethers react with HI at high temperature to produce an alky halide and an alcohol.
R-OR' + HI ⟶ R-I + H-OR'
<em>Benzylic ethers</em> react by an Sₙ1 mechanism by forming the stable benzyl cation.
- PhCH₂-OR + HI ⟶ PhCH₂-O⁺(H)R + I⁻ Protonation of the ether
- PhCH₂-O⁺(H)R ⟶ PhCH₂⁺ + HOR Sₙ1 ionization of oxonium ion
- PhCH₂⁺ + I⁻ ⟶ PhCH₂-I Nucleophilic attack by I⁻
If there is excess HI, the alcohol formed in Step 2 is also converted to an alkyl iodide:
ROH +HI ⟶ R-I + H-OH
Thus, benzyl ethyl ether reacts to form benzyl iodide (a) and ethanol (b).
The ethanol reacts with excess HI in an Sₙ2 reaction to form ethyl iodide (c).
The most stable conformation of 3-isopropyl-1,1dimethylcyclohexane equatorial ethyl group (more stable). The stability of ethylcyclohexane's equatorial conformer exceeds that of its axial conformer by 7.4 kJ/mol.
According to the previous section, the chair conformation with the equatorial methyl group is more stable because it reduces steric repulsion, and as a result, the equilibrium favors the more stable conformer. Strongly favoring the equatorial shape is methylcyclohexane. The methyl group is in close proximity to the axial hydrogens in the axial conformation, which has an energetically unfavorable effect known as a 1,3-diaxial interaction. The methyl group prefers the equatorial shape as a result. The conformation of ethylcyclohexane in which the ethyl group is in the equatorial position is the most stable.
Learn more about equatorial ethyl group here:
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