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2 years ago

A car travels 20km West and then 20 km South. What is the magnitude of it's displacement vector

1 answer:

6 0

c. 28.km
11. Cartesian Coordinates.
X Y
S -3.5 4.5
T 0 -6.5
U 3.5 -2.5
what is angle of resultant vector STU measuring from positive x axis.
24 degrees below x

12. Cartesian Coordinates
Cartesian Coordinates.
X Y
S -3.5 4.5
T 0 -6.5
U 3.5 -2.5
what is magnitude of resultant vector STU
a. 4.9 b. 24 c. 16. d. 18
Seems right option is not there. The right one will be 7./2 ie 9.9

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"A ball with a mass of 0.1 kg is rolling at a velocity of 5 m/s. What is its

Mumz [18]

Answer:

velocity

Explanation:

because the si unit of mass is kg, velocity is m/s, acceleration is m/S2 , moment is kgm2/s . so 5 is given as velocity.

3 0

1 year ago

A car is stopped at a traffic light. When the light turns green at t=0, a truck with a constant speed passes the car with a 20m/

s344n2d4d5 [400]

Answer:

At $t = (70 / 3) \; {\rm s}$ (approximately $23.3 \; {\rm s}$ .)

Explanation:

Note that the acceleration of the car between $t = 0\; {\rm s}$ and $t = 20\; {\rm s}$ ( $\Delta t = 20\; {\rm s}$ ) is constant. Initial velocity of the car was $v_{0} = 0\; {\rm m\cdot s^{-1}}$ , whereas $v_{1} = 35\; {\rm m\cdot s^{-1}}$ at $t = 20\; {\rm s}\!$ . Hence, at $t = 20\; {\rm s}\!\!$ , this car would have travelled a distance of:

$\begin{aligned}x &= \frac{(v_{1} - v_{0})\, \Delta t}{2} \\ &= \frac{(35\; {\rm m\cdot s^{-1}} - 0\; {\rm m\cdot s^{-1}}) \times (20\; {\rm s})}{2} \\ &= 350\; {\rm m}\end{aligned}$ .

At $t = 20\; {\rm s}$ , the truck would have travelled a distance of $x = v\, t = 20\; {\rm m\cdot s^{-1}} \times 20\; {\rm s} = 400\; {\rm m}$ .

In other words, at $t = 20\; {\rm s}$ , the truck was $400\; {\rm m} - 350\; {\rm m} = 50\; {\rm m}$ ahead of the car. The velocity of the car is greater than that of the truck by $35\; {\rm m\cdot s^{-1}} - 20\; {\rm m\cdot s^{-1}} = 15 \; {\rm m\cdot s^{-1}}$ . It would take another $(50\; {\rm m}) / (15\; {\rm m\cdot s^{-1}}) = (10/3)\; {\rm s}$ before the car catches up with the truck.

Hence, the car would catch up with the truck at $t = (20 + (10/3))\; {\rm s} = (70 / 3)\; {\rm s}$ .

3 0

1 year ago

An electron moves with a constant horizontal velocity of 3.0 × 106 m/s and no initial vertical velocity as it enters a deflector

Ghella [55]

Answer:

a = 5.05 x 10¹⁴ m/s²

Explanation:

Consider the motion along the horizontal direction

$v_{x}$ = velocity along the horizontal direction = 3.0 x 10⁶ m/s

t = time of travel

X = horizontal distance traveled = 11 cm = 0.11 m

Time of travel can be given as

$t = \frac{X}{v_{x}}$

inserting the values

t = 0.11/(3.0 x 10⁶)

t = 3.67 x 10⁻⁸ sec

Consider the motion along the vertical direction

Y = vertical distance traveled = 34 cm = 0.34 m

a = acceleration = ?

t = time of travel = 3.67 x 10⁻⁸ sec

$v_{y}$ = initial velocity along the vertical direction = 0 m/s

Using the kinematics equation

Y = $v_{y}$ t + (0.5) a t²

0.34 = (0) (3.67 x 10⁻⁸) + (0.5) a (3.67 x 10⁻⁸)²

a = 5.05 x 10¹⁴ m/s²

7 0

3 years ago

A recipe for a casserole calls for 1 cup of milk. If a chef currently has 0.5 gallons of milk, how many casseroles can the chef

Yakvenalex [24]

Answer:

<em>The chef can make 8 casseroles</em>

Explanation:

<u>Units Conversion</u>

We need to recall 1 gallon = 16 US cups.

A casserole needs 1 cup of milk, and the chef has 0.5 gallons of milk. Those 0.5 gallons are equivalent to 0.5*16 = 8 cups, thus the chef can make 8 casseroles.

4 0

3 years ago

6.1.115 To approximate the speed of the current of a river, a circular paddle wheel with radius 4 ft. is lowered into the water

shtirl [24]

Answer:

1.2 ft/s or 72 ft/min

Explanation:

To solve this problem, we can use the relationship between the angular and linear speed for this particular movement (rotation). As the speed of the current is tangent to the trajectory of the wheel we can define as follows:

$v= \omega r=18 \frac{rev}{min} \times \frac{1min}{60s}\times 4 ft\\v= 1.2 \frac{ft}{s}= 72 \frac{ft}{min}$

The speed of the current is 72 ft/min

5 0

2 years ago