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Lyrx [107]
3 years ago
15

PLEASE ANSWER ASAP: Find the angle that will allow the defender to tackle the ball carrier most efficiently. Also tell how far f

rom the goal line the tackle will occur.

Physics
1 answer:
tiny-mole [99]3 years ago
7 0

Answer:

A.) 51 degree

B.) 26.5 yards

Explanation:

Let assume that time is constant.

The distance between the defender and the ball carrier is 20.6 yard.

Speed = distance/time

6.2 = 20.6/t

t = 20.6/6.2

t = 3.32 s

The distance the defender can cover will be

Distance = 5.1 × 3.32 = 16.95 yards

The angle that will allow the defender to tackle the ball carrier most efficiently will be

Tan Ø = 20.6/16.95

Ø = tan^-1 (1.21568627)

Ø = 50.55

Ø = 51 degree.

The distance from the goal line the tackle will occur will be found by using pythagorean theorem

D = root( 20.6^2 + 16.69^2)

Distance = 26.5 yards

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One event occurs at the origin at t equal to zero, and a second events occurs at the point x=5m along the x-axis at time with ct
Anastasy [175]

Answer:

  • The separation will be spacelike.
  • The first event can't cause the second event, as there exist an frame of reference in which both happens at the same time, in different positions, so, if there were causally connected, it will imply an instant connection, this is faster than light.

Explanation:

We can define the separation between two events (using the + - - - signature)  as :

(\Delta s )^2  = (ct_2 - c t_1 )^2 - (x_2 - x_1)^2

where the separation will be lightlike if is equal to zero, timelike if is positive and spacelike if is negative.

For our problem

c t_1 = 0

x_1 = 0

ct_2 = 4 \ m

x_2 = 5 \ m

(\Delta s )^2  = (4 \ m - 0 )^2 - ( 5 \ m - 0)^2

(\Delta s )^2  = (4 \ m )^2 - ( 5 \ m 0)^2

(\Delta s )^2  = 16 \ m^ 2 - 25 \ m^2

(\Delta s )^2  = - 9\ m^2

So the separation will be spacelike, and the first event can't cause the second event, as there exist an frame of reference in which both happens at the same time, in different positions, so, if there were causally connected, it will imply an instant connection, this is faster than light.

8 0
3 years ago
an object is placed at 19.3 cm in front of a diverging lens with a focal length of -18.7 cm. what is the magnification? enter a
Bezzdna [24]

The magnification <u>is 31.16.</u>

Magnification is the process of increasing the apparent size of something rather than its physical size. This increase is quantified by a calculated number, also called the "factor". If this number is less than 1, it means size reduction, sometimes called size reduction or reduction.

u =  -19.3

f = -18.7 cm.

m = f/f-u

    = -18.7/-18.7 +19.3

   <u>= 31.16</u>

The term magnification refers to the size of the image produced by the lens compared to the size of the object. For lenses: Magnification "m" is the ratio of image height to object height. The magnification of a lens is defined as the ratio of image height to object height. It is also given by image distance and object distance. equal to the ratio of image distance to object distance.

Learn more about magnification here:-brainly.com/question/15744335

#SPJ4

8 0
1 year ago
We place a small pressure sensor at a certain depth in water. with which orientation does the sensor register the greatest press
Dominik [7]
Hydrostatic pressure is independent of directions.

7 0
3 years ago
The type of force that will not cause a change in the speed of an object.
In-s [12.5K]

Explanation:

Balanced forces will cause no change in the speed of an object.

3 0
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Onsider a ball at rest in the middle of a toy wagon. when the wagon is pulled forward, what happens to the ball? why?
zaharov [31]
It moves back because if the wagon moves forw
ard the energy of the ball moves backward
4 0
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