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Lyrx [107]
3 years ago
15

PLEASE ANSWER ASAP: Find the angle that will allow the defender to tackle the ball carrier most efficiently. Also tell how far f

rom the goal line the tackle will occur.

Physics
1 answer:
tiny-mole [99]3 years ago
7 0

Answer:

A.) 51 degree

B.) 26.5 yards

Explanation:

Let assume that time is constant.

The distance between the defender and the ball carrier is 20.6 yard.

Speed = distance/time

6.2 = 20.6/t

t = 20.6/6.2

t = 3.32 s

The distance the defender can cover will be

Distance = 5.1 × 3.32 = 16.95 yards

The angle that will allow the defender to tackle the ball carrier most efficiently will be

Tan Ø = 20.6/16.95

Ø = tan^-1 (1.21568627)

Ø = 50.55

Ø = 51 degree.

The distance from the goal line the tackle will occur will be found by using pythagorean theorem

D = root( 20.6^2 + 16.69^2)

Distance = 26.5 yards

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The λmax of 2,3,4-trimethylhexatriene is 280 nm.

Ethylene has a λmax of 175nm.

Butadiene has a λmax of 220nm.

2-methyl-1,3-butadiene has a λmax or 215nm.

1,3,5-hexatriene has a λmax of 258nm.

Woodward's rules, sometimes known as Woodward-Fieser rules (after Louis Fieser) and named after Robert Burns Woodward, are a number of sets of empirically developed principles that aim to forecast the wavelength of the absorption maximum (max) in an ultraviolet-visible spectrum of a certain molecule.

By using the Woodward Fieser rule,

R- (Alkyl Group) .... +5 nm = 5 × 2 = 10

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Adding 22nm to the λmax of 1,3,5-hexatriene as it has 2 alkyl groups and 2 alkoxy groups to form 2,3,4-trimethylhexatriene.

The λmax of 2,3,4-trimethylhexatriene is 280 nm.

Learn more about Woodward-Fieser here:

brainly.com/question/16982345

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5 0
2 years ago
Megan was doing time trials on her bike around a 400m horizontal track. She took 32 seconds to travel 400m. What was her average
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3 years ago
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How do resistors in parallel affect the total resistance?
4vir4ik [10]

Answer:

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Explanation:

If the resistors are in parallel, the potential difference is the same for each resistor. But the total current is the sum of the currents that pass through each of the resistors. Then

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I = \frac{V}{R_1}+ \frac{V}{R_2} + ... + \frac{V}{R_N} = \left(\frac{1}{R_1} +\frac{1}{R_2} + ... + \frac{1}{R_N}\right)V = \frac{V}{R_T}

where

R_T = \left(\frac{1}{R_1} +\frac{1}{R_2} + ... + \frac{1}{R_N}\right)^{-1} =\sum\limits_{i=1}^N \left(\frac{1}{R_i} \right)^{-1}

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Answer:

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