The force in the horizontal direction is given by 1600cos(20)=1503.5N
Given the mass of m=81kg, we can use F=ma to get acceleration
F/m=a
a=1503.5/81=18.56m/s²
The velocity is given by the integral of the acceleration, V=18.56t m/s
since t=0.28s we get
v=18.56(0.28)=5.197m/s
Answer:
5.44×10⁶ m
Explanation:
For a satellite with period t and orbital radius r, the velocity is:
v = 2πr/t
So the centripetal acceleration is:
a = v² / r
a = (2πr/t)² / r
a = (2π/t)² r
This is equal to the acceleration due to gravity at that elevation:
g = MG / r²
(2π/t)² r = MG / r²
M = (2π/t)² r³ / G
At the surface of the planet, the acceleration due to gravity is:
g = MG / R²
Substituting our expression for the mass of the planet M:
g = [(2π/t)² r³ / G] G / R²
g = (2π/t)² r³ / R²
R² = (2π/t)² r³ / g
R = (2π/t) √(r³ / g)
Given that t = 1.30 h = 4680 s, r = 7.90×10⁶ m, and g = 30.0 m/s²:
R = (2π / 4680 s) √((7.90×10⁶ m)³ / 30.0 m/s²)
R = 5.44×10⁶ m
Notice we didn't need to know the mass of the satellite.
Answer:
63393.8 lbfeet/sec^2
Explanation:
Recall that the weight density of water is 62.5 lb/ft3
F = PA P = hρg = h x 62.5 x 32.2 A = 5 x dh force= integral of (hρg3 x dy) // 3 is width of plane force= integral of ( 62.5 x 32.2 x 3 x hdh) from 2 to 5 force= 62.5 x 32.2 x 3 x (5^2-2^2)/2 = 63393.8 lbfeet/sec^2
Answer:
I think Science,Math and Social
Answer:
The mass of the runner is 75 kg
Explanation:
Recall that the linear momentum is defined as the product of the mass of the object in motion times its velocity: P = m * v
Therefore, for our case we have;
750 kg m/s = m * 10 m/s
solving for the mass (m) we get:
m = 750/10 kg =75 kg
