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grandymaker [24]
3 years ago
13

At 25°C, sound can travel 100 meters across a football field in 0.29 seconds. Determine the velocity of these sound waves in the

direction they travel across the field.
A)
0.0029
m
s


B)
29
m
s


C)
345
m
s


D)
34,500
m
s
Physics
2 answers:
Olin [163]3 years ago
4 0

<u>Answer:</u> The correct answer is Option C.

<u>Explanation:</u>

Velocity is defined as the rate of change of displacement with respect to time. It is a vector quantity because it requires both magnitude and direction. It is expressed in meters/second (m/s).

Mathematically,

\text{Velocity}=\frac{d}{t}

Where,

d = displacement = 100 meters

t = time taken = 0.29 seconds

Putting the values in above equation, we get:

\text{Velocity}=\frac{100m}{0.29s}\\\\\text{Velocity}=344.82m/s\approx 345m/s

The sound wave is moving with a velocity os 345 m/s in the direction of the field.

Hence, the correct answer is Option C.

Nezavi [6.7K]3 years ago
3 0
The correct answer my friend would be C

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The free-body diagram of an apple falling through the air has weight of the apple pointing downwards and the air-resistance on the apple acting upwards.

When an object falls from up to the ground, the object falls under in the influence of acceleration due to gravity.

The vertical component of the force on the apple as it falls trough the air is given as;

∑Fy = 0

Fₙ - W = 0

Fₙ = W

where;

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The free-body diagram of the apple is represented as follows;

                                         ↑ Fₙ

                                         Ο

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Thus, the free-body diagram of an apple falling through the air has weight of the apple pointing downwards and the air-resistance on the apple acting upwards.

Learn more here:brainly.com/question/18770265

6 0
2 years ago
To analyze the motion of a body that is traveling along a curved path, to determine the body's acceleration, velocity, and posit
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To solve this problem we will apply the kinematic equations of linear motion and centripetal motion. For this purpose we will be guided by the definitions of centripetal acceleration to relate it to the tangential velocity. With these equations we will also relate the linear velocity for which we will find the points determined by the statement. Our values are given as

R = 350ft

a_t = 1.1ft/s^2

PART A )

a_c = \frac{V^2}{R}

a_c = \frac{V^2}{350}

Calculate the velocity of the motorcycle when the net acceleration of the motorcycle is 5.25ft/s^2

a = \sqrt{a_t^2+a_r^2}

5.25 = \sqrt{(1.1)^2+(\frac{v^2}{350})^2}

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v = r\omega

42.3877 = 350\omega

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Calculate the angular acceleration of the motorcycle

a_t = r\alpha

1.1 = 350\alpha

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Calculate the time needed by the motorcycle to reach an acceleration of

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\omega = \alpha t

0.1211 = 3.1428*10^{-3}t

t = 38.53s

PART B) Calculate the velocity of the motorcycle when the net acceleration of the motorcycle is 6.75ft/s^2

a = \sqrt{a_t^2+a_r^2}

6.75 = \sqrt{(1.1)^2+(\frac{v^2}{350})^2}

45.5625 = 1.21 + \frac{v^4}{122500}

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PART C)

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a_r = \frac{v^2}{R}

a_r = \frac{21.5^2}{350}

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Calculate the net acceleration of the motorcycle when the velocity of the motorcycle is 21.5ft/s

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a = 1.7187ft/s^2

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6.75 = \sqrt{(1.1)^2+(\frac{v^2}{350})^2}

45.5625 = 1.21 + \frac{v^4}{122500}

v=48.2796ft/s

3 0
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Answer:

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Movement 1 = 18m W

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Therefore, total distance traveled equals :

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18m + 12m = 30m

B) Displacement also measures the movement made by an object. However, Displacement is a vector quantity and therefore, considers both magnitude and direction of travel of the object. Therefore, it measures the overall change in position of the object from its starting position.

Therefore, Displacement of the locomotive equals:

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Answer:

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- subduction (where heavier tectonic plates sink beneath lighter ones).

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