Thermal energy is converted to radiative energy via molecular collisions and released as photons.
Voltage (V)= Current (I) * Resistance (R)
I=V/R=140/2=70A
Hope this helps!
Answer:
Magnitude of Vector = 79.3
Explanation:
When a vector is resolved into its rectangular components, it forms two vector components. These components are named as x-component and y-component, they are calculated by the following formulae:
x-component of vector = (Magnitude of Vector)(Cos θ)
y-component of vector = (Magnitude of Vector)(Sin θ)
where,
θ = angle of the vector with x-axis = 27°
Therefore, using the values in the equation of y-component, we get:
36 = (Magnitude of Vector)(Sin 27°)
Magnitude of Vector = 36/Sin 27°
<u>Magnitude of Vector = 79.3</u>
C is correct. The work-force relation is given by W=F·d, where F is force vector, and d is the displacement vector. The dot is the dot product, which is a measure of how parallel the two vectors are. It can be restated as the product of two vector magnitudes times the cosine of the angle between them. Therefore work is a scalar, not a vector, since the dot product returns a scalar.
Answer:
T1 = 131.4 [N]
T2 = 261 [N]
Explanation:
To solve this problem we must make a sketch of how will be the semicircle, for this reason we conducted an internet search, to find the scheme of the problem. This scheme is attached in the first image.
Then we make a free body diagram, with this free body diagram, we raise the forces that act on the body. Since it is a problem involving static equilibrium, the sum of forces in any direction and moments must be equal to zero.
By performing a sum of forces on the Y axis equal to zero we can find an equation that relates the forces of tension T1 & T2.
The second equation can be determined by summing moments equal to zero, around the point of application of the T1 force. In this way we find the T2 force.
The value of T2, is replaced in the first equation and we can find the value for T1.
Therefore
T1 = 131.4 [N]
T2 = 261 [N]
The free body diagram and the developed equations can be seen in the second attached image.