A study occasionally the effect of anxiety (low vs. high) and stress (low vs. moderate vs. high) on test.
Everyone experiences anxiety occasionally, but persistent anxiety can reduce your quality of life. Though likely best known for altering behavior, worry can have negative effects on our physical health. Anxiety speeds up our heartbeat and breathing, concentrating blood flow to the parts of our brains that need it. You are getting ready for a challenging situation by having this extremely bodily reaction. Test performance may be impacted by anxiety. According to studies, pupils with low levels of test anxiety perform better on multiple-choice question (MCQ) exams than pupils with high levels of anxiety. Studies have occasionally that female students have greater levels of test anxiety than male students.
Learn more about anxiety here:
brainly.com/question/4913240
#SPJ4
Answer:
Explanation:
A.
Given:
Vo = 21 m/s
Vf = 0 m/s
Using equation of Motion,
Vf^2 = Vo^2 - 2aS
S = (21^2)/2 × 9.8
= 22.5 m.
B.
Given:
S = 22.5 + 21 mm
= 22.521 m
Vo = 0 m/s
Using the equation of motion,
S = Vo × t + 1/2 × a × t^2
22.521 = 0 + 1/2 × 9.8 × t^2
t^2 = (2 × 22.521)/9.8
= 4.6
t = 2.14 s
Answer: 11000 N
Explanation:
Given that,
Time required to stop car = 3.0 s
The car's momentum = 33,000
kg m/s
magnitude of force = ?
Recall that impulse is equal to the change in momentum of the car, hence
Impulse (I) = Momentum
(Since I = force x time, then
Force x time = momentum)
F x 3.0 s = 33,000 kg m/s
F = 33,000kg m/s / 3.0s
F = 11,000 N
Thus, 11000N of force was used to stop the car.
Answer:
D:because magmetic force are like factor but the angles of MAGNETIC and FACTORS are same as well!!it soposed to be like force and 1 by 1 to be divided and multiply thus...the DECIMAL have nothing to involved!!
Explanation:
HOPE IT HELPS!!
Answer:
10.77m
Explanation:
The elastic potential energy of the spring when compressed with the mass is converted to the kinetic energy of the mass when released. This ie expressed in the following equation;
where k is the force constant of the spring, e is the compressed length, m is the mass of the block and u is the velocity with which the block leaves the spring after being released.
If we make u the subject of formula from equation (1) we obtain the following;
Given;
e = 0.105m,
k = 4825N/m,
m = 0.252kg,
u = ?
Substituting all values into equation (2) we obtain the following;
The maximum height attained is then obtained from the third equation of motion as follows, taking g as 
v = 0m/s
Hence
