Colonist who belived in complete

The coil of an ac generator has 50 loops and a cross-sectional area of LaTeX: 0.2~m^20.2 m 2 . What is the maximum emf that can

lisov135 [29]

Answer:

Maximum emf in the coil is 100 volt

Explanation:

We have given number of loops in the coil N = 50

Cross sectional area $A=0.2m^2$

Angular speed is given $\omega =5rad/sec$

Magnetic field is given $B=0.2T$

We have to find the maximum emf in the coil

Maximum emf in the coil is given by $e=NBA\omega$

$e=50\times 2\times 0.2\times 5=100volt$

So maximum emf induced in the coil is 100 volt

7 0

3 years ago

5. How much does a 20 m x 10 m x 8 m swimming pool filled with water weigh? Assume that water has a density of 62 kg/m'.

Nookie1986 [14]

Explanation:

First of all we calculate the volume which is 20m×10m×8m= 1600m^3 and then multiply the density by the volume to get the mass which will equal to 99200kg therefore the weight will be

Weight

mass × acceleration due to gravity

=99200kg × 10m^s^2

=992000N

7 0

2 years ago

Please help!!! A river has a constant current of 3 km per hour. If a motorboat, capable of maintaining a constant speed of 20km

PilotLPTM [1.2K]

Construct a vector diagram. It will be a right-angled triangle. One vector (the hypotenuse) represents the heading of the boat, one represents the current and one represents the resultant speed of the boat, which I'll call x. Their magnitudes are 20, 3 and x. Let the required angle = theta. We have:

theta = arcsin(3/20) = approx. 8.63° 

The boat should head against the current in a direction approx. 8.63° to the line connecting the dock with the point opposite, or approx. 81.37° to the shore line. 

x = sqrt(20^2 - 3^2) 
= sqrt(400 - 9) 
= sqrt 391 

The boat's crossing time = 
0.5 km/(sqrt 391 km/hr) 
= (0.5/sqrt 391) hr 
= approx. 0.025 hr 
= approx. 91 seconds

4 0

3 years ago

A cube of water 10 cm on a side is placed in a microwave beam having Ea = 11 kV/m‘ The microwaves illuminate one faceofthe cube,

Shtirlitz [24]

Answer:

The time is 133.5 sec.

Explanation:

Given that,

One side of cube = 10 cm

Intensity of electric field = 11 kV/m

Suppose How long will it take to raise the water temperature by 41°C Assume that the water has no heat loss during this time.

We need to calculate the rate of energy transfer from the beam to the cube