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antiseptic1488 [7]
3 years ago
15

A 3.2 kg particle starts from rest at x = 0 and moves under the influence of a single force Fx = 4 + 15.7 x − 1.5 x 2 , where Fx

is in Newtons and x is in meters. Find the work done by this force on the particle as the particle moves from x = 0 m to x = 1.3 m. Answer in units of J.
Physics
1 answer:
garik1379 [7]3 years ago
8 0

Answer:

Explanation:

Work: This can be defined as the product of force and distance. The unit of work is Joules (J). it can be expressed mathematically as

W = F×d

or

W = \int\limits^b_a {Fx} \, dx.................................. Equation 1

Where b = upper limit, a = lower limit, Fx = expression of force.

<em>Given: a = 0 , b = 1.3 m, Fx = 4 + 15.7x - 1.5x²</em>

Substituting these values into equation 1

<em>W = \int\limits^a_b {(4 + 15.7x - 1.5x^{2} )dx} \,</em>

W = ᵇ[4x + 15.7x²/2-1.5x³/3 +C]ₐ

Work = upper limit - lower limit

Work = ᵃ[4x + 15.7x²/2 - 1.5x³/3 +C] - [4x + 15.7x²/2 + 1.5x³/3 +C]ᵇ............... Equation 2

Substituting the values of a and b into equation 2

Work = [4(1.3) + 15.7(1.3)²/2-1.5(1.3)³/3 + C] - [0 +C]

Work = [5.2 + 26.53 -3.29 + C] - C

Work = 28.44 J

Work done by the force = 28.44 J.

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Example: A wooden crate with mass 100kg is at rest on a stone floor. You know that the coefficients of kinetic and static fricti
alexgriva [62]

Answer

Any force greater 490N

Explanation

The force required just to make an object slide over a rough horizontal surface is any force greater that the static friction which given by;

F=\mu_s mg.............(1)

Given;

\mu_s=0.5\\m=100kg\\g=9.8m/s^2

Hence;

F = 0.5 x 100 x 9.8

F = 490N.

We will only need the coefficient of kinetic friction if we were asked to find the force required to keep the object moving uniformly. Usually, the force needed to keep an object moving uniformly over a rough surface is lesser that which is needed to start its motion.

In this problem, we were only asked to find the minimum force required to make the object move which we have done.

7 0
3 years ago
A train takes 2h to reach station B from station A and 3h to return back to A.The distance between the station is 200km, then it
serg [7]

Answer:

80km/hr

Explanation:

Total distance: 400km

Total time 5 hours

Average speed= distance/time

400/5= 80km/hr

8 0
3 years ago
In a chemical reaction, the total mass of the reactants is 10.0 grams. The total mass of the products must be:
Nookie1986 [14]

Answer: exactly 10.0 grams.

Explanation: The law of conservation of matter states that matter cannot be created or destroyed in a chemical reaction. Therefore, the total mass of the reactants must be the same as the total mass of the products.

7 0
3 years ago
A machine is supplied energy at a rate of 4,000 W and does useful work at a rate of 3,760 W. What is the efficiency of the machi
Dmitry_Shevchenko [17]
                = (3,760 joule/sec) / (4,000 joule/sec)
 
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8 0
3 years ago
Must be 8 letters (Dimensional Analysis escape room)
makkiz [27]

Answer: A-B-C-E-G-K-H-I

Explanation:

Ok, we start at A.

16 pints = x gallons.

We know that:

1 pint = 0.125 al

then:

16pint = 16*(0.125gal) = 2 gal.

The second letter is B.

Now we have:

12,320 yd = X mi

And we know that:

1 mi = 1760 yd.

Then 12,320yd = (12,320/1760) mi = 7mi

the letter is C.

Now we have:

432 cups = X gals

and:

1 cup = 0.0625 gal

then 432 cups = 432*(0.0625 gal) = 27 gal.

The next letter is E.

Now we have:

1/4 ton = X pounds.

And 1 ton = 2000 pounds

then 1/4 ton = (1/4)*2000 pounds = 500 pounds

The next letter is G.

Now we have:

3.5 gal = X ounces.

and we know that:

1 gal = 128 oz

Then:

3.5 gal = 3.5*(128oz) = 448oz

The next letter is K.

Now we have:

1/2 day = x minutes.

and we know that:

1 day = 24*60 min = 1440 min

then 1/2 day = (1/2)*1440 min = 720 min.

The next letter is H.

Now we have:

360 in = x yd

And we know that:

1yd = 36 inches.

then 360 in = (360/36) = 10 yd.

The next letter is I

Now we have:

56 cups = x quarts.

and we know that;

1cup = 0.25 quart

then: 56 cups = 56*0.25 quart = 14

So here this ends.

Then the code is:

A-B-C-E-G-K-H-I

7 0
2 years ago
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