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Vedmedyk [2.9K]
4 years ago
9

URGENT!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
masha68 [24]4 years ago
5 0
4 squared + b squared = 8 squared
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MAKE T THE SUBJECT OF FORMULA G=T+3/7
kaheart [24]

Step-by-step explanation:

G= T+3/7

G-3/7=T

T= G-3/7

6 0
2 years ago
Can i please get help on this question?
Kamila [148]

The answer would be 3.

In order to find this you must place the values in where you see the letters. So start with the letters and plug in.

mx - y

Since m = 1, put that in.

(1)x - y

Since x = 5, put that in

(1)(5) - y

Since y = 2, put that in

(1)(5) - (2)

Now follow the order of operations and solve

(1)(5) - 2

5 - 2

3

5 0
3 years ago
Read 2 more answers
Camryn ate 3 feet of spaghett each day for a week, how many yards of spaghetti did she eat in all
stepan [7]
She ate 7 yards. This is because 3 feet=1 yard, so you can say that she ate 1 yard per day, for 7 days, so that makes it 7 yards.
6 0
3 years ago
In the transmission of digital information, the probability that a bit has high, moderate, and low distortion is 0.02, 0.07, and
Leviafan [203]

Answer:

A. (Table Attached)

B. (See Step 3)

C. 0.06 (See Step 4)

D. NOT independent (See Step 5)

Step-by-step explanation:

<h3 /><h3>STEP 1:</h3>

Name the probabilities:

p₁ = 0.02,   p₂ = 0.07,   p₃ = 0.91

q₁ = 1-p₁ = 0.98 ,   q₂ = 1-p₂ = 0.93 ,   q₃ = 0.09

Let X and Y be the number of bits with high and moderate distortion out of three.

<h3>STEP 2:</h3>

A.

The function will follow multinomial distribution:

f_{XY}(x,y) = P(X=x, Y=y) = \frac{3!}{x!y!(3-x-y)!} (p_1^x)(p_2^y)(p_3^{3-x-y})

Substitute the values and make a table.

TABLE IN ATTACHMENT

<h3>STEP 3:</h3>

B.

We calculate marginal distribution by:

P (X=x)= <em>∑</em> P(X=x,Y=y)

fx(x) can be found by adding all the probabilities in each row for different value of X

For X=0 , ∑P = 0.94157441

For X=1 , ∑P = 0.057624

For X=2 , ∑P = 0.001176

For X=3 , ∑P =0.000008

<h3>STEP 4:</h3><h3>C.</h3>

The mathematic expectation E is the sum of product of each possibility with its probabiity.

E(X)=<em>∑ </em>xP(X=x)

Find E(X):

E(X)= (0*0.9415744)+(1*0.057624)+(2*0.001176)+(3*0.000008)

E(X)=0.06

<h3>STEP 5:</h3>

Condition probability states:

P(A|B)=\frac{P(A,B)}{P(B)}

It can also be written as:

f_{Y|X=1}(y)=\frac{f_{XY}(1,y)}{f_x(1)}

Where f_x(1)\\ = 0.057624

Calculate the quotient:

Y|_{x=1} = 0 ,  f_{Y|_X=1 = 0.862245

Y|_{x=1} = 1 ,  f_{Y|_X=1 = 0.132653

Y|_{x=1} = 2 ,  f_{Y|_X=1 = 0.000510

Y|_{x=1} = 3 ,  f_{Y|_X=1 = 0

Find the dependency:

f_{XY}(y)=f_X(x)f_Y(y)

We found that

f_{Y|_X=1 = 0.862245

Calculate f_Y(1) from summing the column from the table

f_Y(1)=0.17428341+0.007644+0.000084\\f_Y(1)=0.18201141

Which are not equal.

Conclusion:

X and Y are NOT Independent

7 0
4 years ago
Can the product of a whole number and a decimal number less than 1 ever be greater than a whole number
creativ13 [48]
No. The product of a whole number and a decimal number less than 1 will be greater than the whole number multiplied into. For this theorem to be proven. Let us state the mathematical expression into numbers such that <span><span>
1. </span><span> N x 0.1 = N/0.1 < N</span></span> <span><span>
2. </span> 1 x 0.5 = 0.5 </span> <span><span>
3. </span><span> 2 x 0.1 = 0.2</span></span> <span><span>
4. </span><span> 100 x 0.55 = 55</span></span> 

These three examples and stances then suggest the claim that the product is not equal to the whole number used in the equation.



7 0
3 years ago
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