In preparation of aspirin why is water added

1 answer:

8 0

The formation of aspirin will proceed faster if acetic anhydride is used in place of acetic acid.

However, acetic anhydride will hydrolyze in the presence of water to form acetic acid, slowing down the reaction.

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a solution is prepared by dissolving 55g of CaCl2 into 300g of water. if the Kf of water is -1.86 c/m, shat is the freezing poin

Zepler [3.9K]

Answer:

Relation between , molality and temperature is as follows.

T =

It is also known as depression between freezing point where, i is the Van't Hoff factor.

Let us assume that there is 100% dissociation. Hence, the value of i for these given species will be as follows.

i for = 3

i for glucose = 1

i for NaCl = 2

Depression in freezing point will have a negative sign. Therefore, d

depression in freezing point for the given species is as follows.

Therefore, we can conclude that given species are arranged according to their freezing point depression with the least depression first as follows.

Glucose < NaCl <

Explanation:

3 0

3 years ago

Are these ramen noodles expired?

laiz [17]

Answer:

i think so

Explanation:

just eat them anyways

6 0

3 years ago

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How many Iron atoms (Fe) are represented in the following formula?

rosijanka [135]

Answer:

Explanation:

pa mark brainliest

8 0

2 years ago

An electrochemical cell is powered by the half reactions shown below.

andrezito [222]

Reduction reactions are those reactions that reduce the oxidation number of a substance. Hence, the product side of the reaction must contain excess electrons. The opposite is true for oxidation reactions. When you want to determine the potential difference expressed in volts between the cathode and anode, the equation would be: E,reduction - E,oxidation.

To cancel out the electrons, the e- in the reactions must be in opposite sides. To do this, you reverse the equation with the negative E0, then replacing it with the opposite sign.

Pb(s) --> Pb2+ +2e- E0 = +0.13 V
Ag+ + e- ---> Ag E0 = +0.80 V

Adding up the E0's would yield an overall electric cell potential of +0.93 V.

7 0

3 years ago

5. What are the relative rates of diffusion for methane, CH, and oxygen, O2? If O2 la travels 1.00 m in a certain amount of time

11Alexandr11 [23.1K]

Answer:

The relative rates of diffusion for methane and oxygen is 1.4142.

Methane gas will be able to travel 1.4142 meter in the same conditions.

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. Mathematically written as:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$