Question

With what speed must a ball be thrown vertically from ground level to rise to a maximum height of 35 m?

Answer 1

First there are many ways to approach this problem. The simplest and most direct in my opinion is this approach:

vf^2=v1^2+2ad
so when the height reaches a maximum of 35m the velocity is zero for a split second before starting to fall. So we set vf=0 and solve for v1.

v1=sqrt(2gd)=sqrt(2*9.8*35)= 26.2m/s
for initial velocity needed to reach 35m height.

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