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valentinak56 [21]
3 years ago
11

Step 1, when solving a two dimensional, multi-charge problem, is to define the vectors. Please identify the next five steps, in

order.
Physics
2 answers:
Lana71 [14]3 years ago
5 0

Answer:

Step 1, when solving a two dimensional, multi-charge problem, is to define the vectors. Please identify the next five steps, in order.

Step 2: calculate a & b mag

Step 3: calculate x,y components

Step 4: sum vector components

Step 5: calculate magnitude of R

Step 6: calculate direction of R

Maksim231197 [3]3 years ago
4 0

Answer: The next 5 steps are.

step 2: Find the magnitude of vectors.

step 3: Calculate 'x' and 'y' components.

step 4: Sum the above obtained vector components.

step 5: Calculate the magnitude of Resultant Vector.

Step 6: Determine the direction of the resultant vector.

Explanation:

Let the two vectors be 'A' and 'B'.

Let A = x_{1} \hat{i}+y_{1}\hat{j}+z_{1}\hat{k} and B = x_{2} \hat{i}+y_{2}\hat{j}+z_{2}\hat{k}

It is given that, when solving a two dimensional, multi-charge problem, is to define the vectors.

So, step 1 is to define the vectors A and B.

In step 2, we find the magnitude of the vectors by,

|A|=\sqrt{x_1^2+y_1^2+z_1^2}

|B|=\sqrt{x_2^2+y_2^2+z_2^2}

In step 3, we find the components 'x' and 'y'

Then in step 4, we sum the components. Now we get the Resultant vector (R).

In step 5, Calculate the magnitude of 'R' using the above formula to find magnitude.

In step 6, we determine the direction of 'R'.

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2 years ago
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3 years ago
A 20 KeV electron emits two bremsstrahlung photons as it is being brought to rest in two successive decelerations. The wavelengt
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Answer:

λ₁ = 87.5 10⁻¹² m ,  λ₂ =  2.175 10⁻¹⁰ m,    E₂ = 5.8 10³ eV

Explanation:

In this case you can use the law of conservation of energy, all the energy of the electron is converted into energized emitted photons

Let's reduce to the SI system

          E₀ = 20 10³ eV (1.6 10⁻¹⁹ J / 1eV) = 3.2 10⁻¹⁵ J

          Δλ = 1.30 A = 0.13 nm = 0.13 10⁻⁹ m

          Ef = E₁ + E₂

         E₀ = Ef

         E₀ = E₁ + E₂

The energy can be found with the Planck equation

          E = h f

          c = λ f

          f = c / λ

          E = hc / λ

They indicate that the wavelength of the second photon is

 

           λ₂ =  λ₁ +0.130 10⁻⁹

We replace

           E₀ = hv / λ₁ + hc / ( λ₁ + 0.130 10⁺⁹)

           E₀ / hv = 1 / λ₁ + 1 / ( λ₁ + 0.13 10⁻⁹)

          3.2 10⁻¹⁵ / (6.63 10⁻³⁴ 3 10⁸) = ( λ₁ + 0.13 10⁻⁹ +  λ₁) /  λ₁ ( λ₁ + 0.13 10⁻⁹)

          1.6 10¹⁰ ( λ₁² +0.13 10⁻⁹  λ₁) = 2  λ₁ + 0.13 10⁻⁹

           λ₁² + 0.13 10⁻⁹  λ₁ = 1.25 10⁻¹⁰  λ₁ + 8.125 10⁻²¹

            λ₁² + 0.005 10⁻⁹  λ₁ = 8.125 10⁻²¹

            λ₁² + 5 10⁻¹²  λ₁ - 8.125 10⁻²¹ = 0

Let's solve the second degree equation

            λ₁ = [-5 10⁻¹² ±√((5 10⁻¹²)² + 4 8.125 10⁻²¹)] / 2

    λ₁ = [-5 10⁻¹² ±√(25 10⁻²⁴ +32.5 10⁻²¹)] / 2 = [-5 10⁻¹² ±√ (32525 10⁻²⁴)] / 2

             λ₁ = [-5 10⁻¹² ± 180 10⁻¹²] / 2

            λ₁ = 87.5 10⁻¹² m

             λ₂ = -92.5 10⁻¹² m

We take the positive wavelength

The wavelength of the photons is

            λ₁ = 87.5 10⁻¹² m

            λ₂ =  λ₁ + 0.13 10⁻⁹

             λ₂ = 87.5 10⁻¹² + 0.13 10⁻⁹

             λ₂ = 0.2175 10⁻⁹ m = 2.175 10⁻¹⁰ m

The energy after the first deceleration is

            E₂ = E₀ –E₁

            E₂ = E₀ –hc / λ₁

            E₂ = 3.2 10⁻¹⁵ - 6.63 10⁺³⁴ 3 10⁸ / 87.5 10⁻¹²

            E₂ = 3.2 10⁻¹⁵ - 2.27 10⁻¹⁵

             E₂ = 0.93 10⁻¹⁵ J

             E₂ = 0.93 10⁻¹⁵ J (1 eV / 1.6 10⁻¹⁹ J)

             E₂ = 5.8 10³ eV

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3 years ago
The speed of sound at temperature of________in the air is 360m/s.​
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29=0.6T

0.6T/29

T=6/290 so change it to simplest form and us formulas good luck

4 0
3 years ago
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