Question

A child sits 1.6 m from the center of a merry go round that makes one complete revolution in 4.7 s. What is his angular acceleration?

Answer 1

Answer: angular acceleration = $2.86\ rad/sec^{2}$

Given:

Distance from center of axis = 1.6 m

Time taken to complete one revolution = 4.7 sec

Therefore, we can evaluate the angular acceleration using the following formula:

$\alpha = r\times \omega^{2}$

$\alpha = r\times (\frac{2\pi}{T})^{2}$

$\alpha = 1.6\times (\frac{2\times3.14}{4.7})^{2}$

$\alpha$ = $2.86\ rad/sec^{2}$