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Lelechka [254]
2 years ago
12

If the force of attraction (gravity) on the moon is 1/6 that of the force on Earth, what would

Physics
1 answer:
Aloiza [94]2 years ago
4 0

I believe that you would weigh around 68 or 69 N, or 7 kilograms.

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Electromagnetic waves travel through space at a speed of _____.
Veseljchak [2.6K]
The answer is C 300,000 kilometers per second

6 0
2 years ago
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An open pipe of length 0.39 m vibrates in the third harmonic with a frequency of 1400 Hz what is the distance from the center of
Svetach [21]

Length of the pipe = 0.39 m

Number of harmonics = 3

Now there are 3 loops so here we can say

3\times \frac{\lambda}{2} = 0.39

\lambda = 0.26 m

now here at the center of the pipe it will form Node

we need to find the distance of nearest antinode

So distance between node and its nearest antinode will be

d = \frac{\lambda}{4}

d = \frac{0.26}{4} = 0.065 m = 6.5 cm

So the distance will be 6.5 cm

3 0
2 years ago
In the lab, you submerge 100 g of 40°C nails in 200 g of 20°C water. (The specific heat of iron is 0.12 cal/g # °C.) Equate the
Deffense [45]

Answer:

Final temperature of the mixture becomes

T = 21.13^oC

Explanation:

Here we know that heat given by the nail is equal to the heat absorbed by water

So here we know that heat to change the temperature is given as

Q = ms\Delta T

so by equating the heat we have

m_{iron}s_{iron}\Delta T = m_{water}s_{water}\Delta T

now we have

100 (0.12) (40 - T) = 200 (1) (T - 20)

4.8 - 0.12 T = 2T - 40

44.8 = 2.12 T

T = 21.13^oC

5 0
2 years ago
The longest passenger liner ever built was the France, 66,348 tons and 315.5 long. Suppose its front end passes the edge of a pi
Kaylis [27]

Answer:

The back end of the vessel will pass the pier at 4.83 m/s

Explanation:

This is purely a kinetics question (assuming we're ignoring drag and other forces) so the weight of the boat doesn't matter. We're given:

Δd = 315.5 m

vi = 2.10 m/s

a = 0.03 m/s^2

vf = ?

The kinetics equation that incorporates all these variables is:

vf^2 = vi^2 + 2aΔd

vf = √(2.1^2 + 2(0.03)(315.5))

vf = 4.83 m/s

5 0
2 years ago
And observer reviews for identical objects that are traveling at speed close to the speed of light in their legs be used to rank
soldier1979 [14.2K]

Answer:

C :)

Explanation:

5 0
3 years ago
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