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Maksim231197 [3]
3 years ago
12

Type the correct answer in the box. What’s the velocity of the balloon? Use . A hot-air balloon with a mass of 400 kilograms mov

es across the sky with 3,200 joules of kinetic energy. The velocity of the balloon is meters/second.
Physics
2 answers:
alexandr1967 [171]3 years ago
7 0

Answer:

4 m/s would be the answer.

Ulleksa [173]3 years ago
4 0

Answer:

4 m/s would be the answer.

Explanation:

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A satellite of mass m is moving in a circular orbit around the earth at a constant speed v and at an altitude h above the earth'
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Fa=Fcp=>k*Mp*m/(Rp+r)²=mv²/(Rp+r)=>v=√(k*Mp/(Rp+r))=√(6.67*10⁻¹¹*5.98*10²⁴/(6371*10³+1000*10³))=√(39.88*10¹³/(7371*10³))=√(5.41*10⁷)=7355.53 m/s


Check the calculations again !


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In her hand, a softball pitcher swings a ball of mass 0.245 kg around a vertical circular path of radius 59.8 cm before releasin
GuDViN [60]

Answer:

The velocity is v_b = 20.17 \ m/s

Explanation:

From the question we are told that

   The mass of the ball is  m = 0.245 \ kg

   The radius is  r =  59.8 \  cm  =  0.598 \ m

   The force is  F =  30.9 \ N

   The speed of the ball is  v = 16.0 \ m/s.

Generally the kinetic energy at the top of the circle is mathematically represented as

    K_t  =  \frac{1}{2} *  m  *  v^2

=> K_t  =  \frac{1}{2} *  0.245   *  16.0 ^2  

=> K_t  =  31.36 \ J  

Generally the work done by the force applied on the ball from the top to the bottom  is mathematically represented as

       W =  F *  d

Here  d is the length of  a semi - circular arc which is mathematically represented as

       d =  \pi * r

So

      W =  30.9 *  0.598

      W = 18.48 \ J

Generally the kinetic energy at the bottom is mathematically represented as

      K_b  =  \frac{1}{2} *  m *  v_b^2

=>    K_b  =  \frac{1}{2} *  0.245  *  v_b^2

=>   K_b  =  0.1225  *  v_b^2

From the law of energy conservation

     K_t +  W  =K_b

=>    31.36+  18.48 = 0.1225  *  v_b^2

=>    v_b = 20.17 \ m/s

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