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3 years ago

If carla does 25 jumping jacks 3 times per day how many jumping jacks will she do in 7 days?

2 answers:

6 0

Carla will do 525 jumping jacks in 7 days.
First, you multiply 25 by 3. You get 75.
Then you have to multiply 75 by 7. You get 525.
You multiply 25 by 3 to get 75 because that's how many she does in 1 day. And you multiply 75 by 7 to get 525 because she does 75 jumping jacks per day, for 7 days.

ryzh [129]3 years ago

5 0

How many jumping jacks does carla do in one day?
carla does 25 jumping jacks 3 times per day

25 + 25 + 25 = 75 jumping jacks per day

carla does 75 jumping jacks per day, how many will she do in 7 days?

7 x 75 = 525

Carla will do 525 jumping jacks in 7 days

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2 years ago

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Answer:

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Step-by-step explanation:

To translate 2 left, subtract 2 from every x-value.

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W' = W +(-2, 6) = (4-2, 8+6)

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2 years ago

Consider the radical equation (3√6-x)+4=-8. Explain why the calculation in Problem 1 does not produce a solution to the equation

murzikaleks [220]

Answer:

See explanation below

Step-by-step explanation:

First we will solve the radical equation (which I guess was problem 1),

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$3\sqrt{6-x}+4=-8\\ 3\sqrt{6-x}=-8-4\\ 3\sqrt{6-x}=-12\\\sqrt{6-x}=-4$

Now we will solve the equation by squaring both sides of the equation:

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$3\sqrt{6-x} +4= -8\\3\sqrt{6-(-10)} +4=-8\\3\sqrt{16}+4 = -8\\ 3(4)+4 = -8\\12 + 4 = -8$

This happens because when we first squared both sides of the equation in the first part of the problem we missed one value for x (remember that all roots have 2 answers, a positive one and a negative one) while squares are always positive.

When we squared the root, we missed one value for x and that is why the calculation does not produce a solution to the equation.

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