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EastWind [94]
3 years ago
10

Sylvanite is a mineral that contains 28.0% \% gold by mass. How much sylvanite would you need to dig up to obtain 34.0g g of gol

d?
Physics
1 answer:
Irina-Kira [14]3 years ago
3 0
Since it is said the 1g of mineral contains 28% of gold which is equivalent to .28g of gold. <span>Thus, .28 gram of Gold = 100 grams of Minerals
        => 1g of Gold = 100/28 grams of Minerals
        => 34grams of gold = 100/28 * 34 g of Minerals
        => 34 grams of gold = 952 grams of Minerals</span>
Therefore, it needs 952 grams of Sylvanite minerals in order to have 34 grams of Gold.



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