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k0ka [10]
4 years ago
9

a 3.46 kg box is sitting at rest on a flat floor. a.) what is the weight of the box. b.) what is the normal force on the box

Physics
1 answer:
just olya [345]4 years ago
4 0

A) The weight of the box is given by:

W = mg

W = weight, m = mass, g = gravitational acceleration

Given values:

m = 3.46kg, g = 9.81m/s²

Plug in and solve for W:

W = 3.46(9.81)

W = 33.9N

B) The box is sitting at rest on the floor. This means that the box is in equilibrium; the two forces acting on it, its weight and the normal force that the floor exerts on it, are equal in magnitude and opposite in direction. Therefore the normal force N acting on the box has a magnitude of 33.9N

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A point charge gives rise to an electric field with magnitude 2 N/C at a distance of 4 m. If the distance is increased to 20 m,
worty [1.4K]

Answer:

0.08 N/C

Explanation:

Electric Field: This is defined as the force per unit charge exerted at a point. The expression for electric field is given as,

E = Kq/r².............................. Equation 1

Where E = Electric Field, q = Charge, k = proportionality constant, r = distance.

making q the subject of the equation,

q = Er²/k............................... Equation 2

Given: E = 2 N/C, r = 4 m,

Substitute into equation 2

q = 2(4)²/k

q = 32/k C.

When r is increased to 20 m,

E = k(32/k)/20²

E = 32/400

E = 0.08 N/C.

Hence the electric Field = 0.08 N/C

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4 years ago
Go to your backyard or to your high school’s basketball court or tennis court and try out this experiment to see if you can pred
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Answer:1 Sprint 54 cm Beyond

2 Sprint 41 cm Beyond

3 Sprint 68 cm Beyond

4 Sprint 32 cm Beyond

5 Sprint 44 cm Beyond

6 Jog   31 cm Beyond

7 Jog         22 cm Beyond

8 Walk 17 cm Beyond and left

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Explanation:

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3 years ago
If two waves collide and form a temporary smaller wave, the interference is ?
Alecsey [184]
Destructive interference occurs when waves form smaller waves.
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4 years ago
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Who founded Electronic Arts?
GREYUIT [131]

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3 years ago
Pun zapato de golf tiene 10 tacos cada uno con un área de 0.01 pulgadas en contacto con el piso suponga que caminar hay un insta
Mars2501 [29]

Answer:

Las presión ejercida por los tacos sobre el suelo es 900 libras por pulgada cuadrada.

Explanation:

Según la Física, comprendemos que la presión es igual a la fuerza dividida por área. En este caso, el peso de la persona dividida por área total de los tacos de los zapatos de golf suponiendo una distribución uniforme de la fuerza. Es decir:

\sigma = \frac{W}{n\cdot A_{T}} (Eq. 1)

Donde:

\sigma - Presión, medida en libras por pulgada cuadrada.

W - Peso de la persona, medida en libras.

n - Cantidad de tacos en los zapatos, adimensional.

A_{T} - Área del taco, medida en pulgadas cuadradas.

Si conocemos que W = 180\,lb, n = 20 y A_{T} = 0.01\,in^{2}, la presión es:

\sigma = \frac{180\,lb}{(20)\cdot (0.01\,in^{2})}

\sigma = 900\,psi

Las presión ejercida por los tacos sobre el suelo es 900 libras por pulgada cuadrada.

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