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3 years ago

a 3.46 kg box is sitting at rest on a flat floor. a.) what is the weight of the box. b.) what is the normal force on the box

Physics

1 answer:

just olya [345]3 years ago

4 0

A) The weight of the box is given by:

W = mg

W = weight, m = mass, g = gravitational acceleration

Given values:

m = 3.46kg, g = 9.81m/s²

Plug in and solve for W:

W = 3.46(9.81)

W = 33.9N

B) The box is sitting at rest on the floor. This means that the box is in equilibrium; the two forces acting on it, its weight and the normal force that the floor exerts on it, are equal in magnitude and opposite in direction. Therefore the normal force N acting on the box has a magnitude of 33.9N

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A box is being moved with a velocity (v) by a force P (parallel to v) along a level horizontal floor. The normal force is (Fn),

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Answer:

Force (P) : Positive

Normal Force (Fn) : Zero

Weight (mg) : Zero

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FOR NORMAL FORCE (Fn) AND WEIGHT (W):

Since, normal force and weight are perpendicular to the motion of the box. Therefore, θ = 90°

Hence,

W = Fn d Cos 90°= mg d Cos 90°

W = Fn d(0) = mg d (0)

W = 0

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FOR KINETIC FRICTIONAL FORCE (fk):

Since, kinetic frictional force acts in the opposite direction of motion of the box. Therefore, θ = 180°

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x
12 > 10
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