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Valentin [98]
3 years ago
13

Be sure to answer all parts. For the equilibrium 2 H2S(g) ⇌ 2 H2(g) + S2(g) Kc = 9.0 × 10−8 at 700°C the initial concentrations

of the three gases are 0.740 M H2S, 0.740 M H2, and 0.370 M S2. Determine the equilibrium concentrations of the gases.
Chemistry
1 answer:
mina [271]3 years ago
7 0

Answer:

Explanation:

2H2S(g) ⇌ 2H2(g) + S2(g)

0.74 0.74 0.37 (initial)

0.74 - 2x 0.74 + 2x 0.37 + x (at equilibrium)

(0.74 + 2x)^2 * (0.37 + x)/(0.74 - 2x)^2

= 9*10^-8

x = -0.356

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