Answer:
A.
Explanation:
A) The number of H+ ions in the substance is equal to the number of OH-ions.
Combustion equation of n-hexane:
2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O
a)
Assuming we have 100 moles of air,
Oxygen = 20.9 moles
n-hexane required = 20.9/19 x 2
= 2.2 moles
LFL = Half of stoichometric amount = 2.2 / 2 = 1.1
LFL n-hexane = 1.1%
b)
1.1 volume percent required for LFL
1.1% x 1
= 0.0011 m³ of n-hexane required
Answer:
Distillation and using Chromatography
Explanation:
Distillation:
based on using boiling point.
Ex: separating a mixture of water and sugar by boiling the water away.
Chromatography:
based on absorption
Ex: separating the different colours that make up a black marker
Answer:
Double bond
Chemical compounds with double bonds.
Ethylene Carbon-carbon double bond.
Acetone Carbon-oxygen double bond.
Dimethyl sulfoxide Sulfur-oxygen double bond.
Diazene Nitrogen-nitrogen double bond.
Explanation:
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Answer:
Keq = [CO₂]/[O₂]
Explanation:
Step 1: Write the balanced equation for the reaction at equilibrium
C(s) + O₂(g) ⇄ CO₂(g)
Step 2: Write the expression for the equilibrium constant (Keq)
The equilibrium constant is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It only includes gases and aqueous species. The equilibrium constant for the given system is:
Keq = [CO₂]/[O₂]