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3 years ago

Calculate the grams of sodium hydroxide formed when 2.24 moles of sodium oxide react with water

1 answer:

8 0

M = GFM × N

Sodium Oxide

s Na O
v 1 2
s 2 1
d 2 1
f Na2O

Na2O

2 × 23 = 46
1 × 16 = 16
46 + 16 = 62g

GFM = 62g
N = 2.24 moles
M = ?

M = GFM × N
M = 62,2 × 2.24
M = 138.88g

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Force of launched skyrocket = 10 N

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<h3>Ferric Oxide:-</h3>

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,3){\bf Fe}\put(0,0){\bf -3}\put(4,3){\sf O}\put(4,0){\bf -2}\put(0.2,2.9){\vector(4,-3){3.5}}\put(3.8,2.9){\vector(-4,-3){3.5}}\end{picture}$

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<h3>Calcium Hydroxide:-</h3>

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,3){\bf Ca}\put(0,0){\bf 2}\put(4,3){\sf OH}\put(4,0){\bf -1}\put(0.2,2.9){\vector(4,-3){3.5}}\put(3.8,2.9){\vector(-4,-3){3.5}}\end{picture}$

$\\ \sf\longmapsto Ca(OH)_2$

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