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stellarik [79]
4 years ago
10

The power rating of a clock is 10 W, and the cost of electrical energy is $0.15 per kilowatt-hour. Rounded to the nearest cent,

how much does it cost to run the clock for one whole week?
Physics
2 answers:
Dimas [21]4 years ago
7 0
Well, don't you just need to multiply 10w times 0.15 
leva [86]4 years ago
3 0

Answer:

$0.252

Explanation:

The power rating of an appliance suggests the amount of energy consumed per unit time.

The power rating of clock is given as 10 W.

It runs for 1 week. 1 week = 7 days = 7 ×24 hours = 168 hours

Consumption of electrical energy in one week would be = 1680 Watt-hour = 1.68 kW-hr

It is given that the cost of electrical energy is $0.15 per kW-hr

Thus, the total cost to run the clock would be:

$0.15 per kW-hr × 1.68 kW-hr = $0.252

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A projectile is shot at an angle 45 degrees to the horizontalnear the surface of the earth but in the absence of air resistance.
ivann1987 [24]

Answer:

v₂ = 176.24 m/s

Explanation:

given,

angle of projectile = 45°

speed = v₁ = 150 m/s

for second trail

speed = v₂ = ?

angle of projectile = 37°

maximum height attained formula,

H_{max}= \dfrac{v^2 sin^2(\theta)}{g}

now,

H_{max}= \dfrac{v_1^2 sin^2(\theta_1)}{g}

H_{max}= \dfrac{v_2^2 sin^2(\theta_2)}{g}

now, equating both the equations

\dfrac{v_2^2}{v_1^2}=\dfrac{sin^2(\theta_1)}{sin^2(\theta_2)}

\dfrac{v_2^2}{150^2}=\dfrac{sin^2(45^0)}{sin^2(37^0)}

   v₂² = 31061.79

   v₂ = 176.24 m/s

velocity of projectile would be equal to v₂ = 176.24 m/s

8 0
3 years ago
Perpendicular slope to 3x-y=4
Mashcka [7]
Perpendicular slope would be 1/3. so the equation will be Y=1/3x -4

4 0
3 years ago
How does friction affect the distance of an object?
stiv31 [10]
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4 0
3 years ago
What scientific observation did Edwin Hubble use to determine distances between galaxies?
Cerrena [4.2K]

Answer: the expanding universe

Explanation:

Hope that helps!

7 0
3 years ago
what is the force of friction between an 80kg box and the ground on Earth if the coefficient is 0.2?​
Reil [10]

Answer:

160N

Explanation: When 80kg mass is one group . It's reaction force acting on a ground.

Weight of the object = 80*10

= 800 N

Here we are given cofficient of static friction its 0.2. It should be smaller than 1

Friction force = Reaction * Friction Cofficient

Reaction = 800N ( Considering Vertical Equilibrium )

F = 800* 0.2

F = 160N

3 0
3 years ago
Read 2 more answers
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