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kiruha [24]
3 years ago
15

How does friction affect the distance of an object?

Physics
1 answer:
stiv31 [10]3 years ago
4 0
It slows the object down so it cannot move well and evetually the object cannot be pushed and farther
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If a train travels at a speed of 40 km/h for 3 hours, how far will it travel
VikaD [51]
120 km/3 hours. 40/1=?/3 1x3=3 hours so 40x3=120 km
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Someone help me please!!
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Pretty sure it's C) condensation because all of the others required heat to be added
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In a laboratory experiment, a diffraction grating produces an interference pattern on a screen. If the number of slits in (inclu
Darya [45]

Answer:

Explanation:

When the number of slits increases, the intensity of fringes increases.

So, the fringes appear to be more bright.

As we know that the fringe width is inversely proportional to the number of slits, so as the number of slits increases, the fringe width decreases, hence the fringes are narrower, bright and close together.

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3 years ago
two soccer players run toward each other. one player has a mass of 85 kg and runs west with a speed of 8 m/s, while the other ha
marissa [1.9K]

Answer:

Total momentum, p = 55 kg-m/s

Explanation:

It is given that,

Mass of player 1, m₁ = 85 kg

Mass of player 2, m₂ = 105 kg

Speed of player 1, v₁ = -8 m/s (west)

Speed of player 2, v₂ = 7 m/s (east)

Momentum is equal to the product of mass and velocity. For this system, momentum is given by :

p=m_1v_1+m_2v_2

p=85\ kg\times (-8\ m/s)+105\ kg\times 7\ m/s

p = 55 kg-m/s

The total momentum of the system made up of the two players is 55 kg-m/s.

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3 years ago
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Please answer this question
sergij07 [2.7K]

Explanation:

m = kg. v=m/s. g=m/s^2. h= m

>>1/2mv^2=mgh

>>1/2mv^2=mgh>> kg*(m/s)^2= kg*m/s^2*m

>>1/2mv^2=mgh>> kg*(m/s)^2= kg*m/s^2*m>>kg m^2/s^2=kg m^2/s^2 the fraction 1/2 won't be able to make any changes to to the dimensional expression of energy i.e half of energy is still energy therefore you can neglect the number .

<u>>>kg m^2/s^2=kg m^2/s^2</u><u> </u>

<u>></u><u>></u><u>J</u>= J

3 0
3 years ago
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