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valentinak56 [21]
3 years ago
10

Perpendicular slope to 3x-y=4

Physics
1 answer:
Mashcka [7]3 years ago
4 0
Perpendicular slope would be 1/3. so the equation will be Y=1/3x -4

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The sputnik one satellite orbiting earth mass equals 5.98×10 to the 24th power kilograms in a circle of radius 6.96×10 to the si
nika2105 [10]

Answer:

7572 m/s

Explanation:

The force between two masses separated by a distance r is given as:

F=G\frac{m_1m_2}{r^2}

Where F is the attractive force between 2 masses, m1 and m2, r is the distance between the centres of the masses and G is the universal gravitation constant, which is 6.674*10^-11 Nm^2/kg^2

The mass of the earth (m_1) is far greater than the mass of the sputnik (m_2). Therefore m_1m_2=m_1. The mass of the sputnik is neglected, therefore:

F=G\frac{m_1}{r^2}=\frac{(6.674*10^{-11})(5.98*10^{24})}{(6.96*10^6)^2} = 8.2389N

But F is actually centripetal acceleration, a = v²/r

8.2389 = v^2 / 6.96*10^6\\v=7572m/s

6 0
3 years ago
Why is most space exploration accomplished with spacecraft that do not have astronauts on board
Olin [163]
Because of the enormous expense of creating conditions aboard
a spacecraft in which astronauts can survive, and the huge extra
weight and expense of guaranteeing their safety.
6 0
3 years ago
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A solar panel is used to collect energy from the sun and change it into other forms of energy. The picture below shows some sola
irakobra [83]
C I’m pretty sure!!!!!
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A rocket passes you at a speed of 0.85c, and you measure its length to be 35.0 m. What is its measured length when at rest?
viktelen [127]

Answer:

66.4 m

Explanation:

To solve the problem, we can use the length contraction formula, which states that the length observed in the reference frame moving with the object (the rocket) is given by

L=L_0 \sqrt{1-(\frac{v}{c})^2}

where

L_0 is the proper length (the length measured from an observer at rest)

v is the speed of the object (the rocket)

c is the speed of light

Here we know

v = 0.85c

L = 35.0 m

So we can re-arrange the equation to find the length of the rocket at rest:

L_0 = \frac{L}{\sqrt{1-(\frac{v}{c})^2}}=\frac{35.0}{\sqrt{1-(\frac{0.85c}{c})^2}}=66.4 m

8 0
3 years ago
What is the mass of a stone moving at a speed of 15 meters/second and having a momentum of 7.5 kilogram - meters / seconds
Elanso [62]

Answer:

0.5 kg

Explanation:

The momentum of an object is defined as

p = mv

where

m is the mass

v is the velocity

In this problem we have,

v = 15 m/s is the velocity of the stone

p = 7.5 kg m/s is the momentum

Solving for m, we can find the mass of the stone:

m=\frac{p}{v}=\frac{7.5 kg m/s}{15 m/s}=0.5 kg

4 0
3 years ago
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