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Ymorist [56]
2 years ago
11

A 7.00 kg bowling ball is held 2.00 m above the ground. Using g- 9.8 m/s^2, how much energy does the bowling ball have due to it

's position?
A. 68.6 J
B. 137 J
C. 274 J
D. 960 J
Physics
1 answer:
Alexeev081 [22]2 years ago
3 0
It should be B.137 just took the test.
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Answer : The energy of one photon of hydrogen atom is, 3.03\times 10^{-19}J

Explanation :

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Putting the values, in above equation, we get:

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E=\frac{hc}{\lambda}

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Putting the values, in this formula, we get:

E=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{6.56\times 10^{-7}m}

E=3.03\times 10^{-19}J

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