Answer:
Twice as much.
Explanation:
That's because the freezing point depression depends on the total number of solute particles.
C₆H₁₂O₆(s) ⟶ C₆H₁₂O₆(aq)
0.01 mol of C₆H₁₂O₆ gives 0.01 mol of solute particles.
NaCl(s) ⟶ Na⁺(aq) + Cl⁻(aq)
1 mol of NaCl gives 0.01 mol of Na⁺(aq) and 0.01 mol of Cl⁻(aq).
That's 0.02 mol of particles, so the freezing point depression of 0.01 mol·L⁻¹ NaCl will be twice that of 0.01 mol·L⁻¹ C₆H₁₂O₆.
Answer:
Explanation:
Inclined Plane: Easy Lifting. An inclined plane is simply an even, sloping surface. ...
Wedge: Splitting and Separating. ...
Screw: Fastening and Moving. ...
Lever: Multiplying Force. ...
Wheel and Axle: Rolling. ...
Pulley: Hoisting Heavy Loads. ...
Scissors: Making the Cut. ...
Hand Truck: Mover's Friend.
There are 8.61 × 10²⁰ atoms in 0.290 g P₂O₅.
Step 1. Convert <em>grams of P₂O₅ to moles of P₂O₅</em>.

Step 2. Convert <em>moles of P₂O₅ to molecules of P₂O₅</em>.


Step 3. Convert <em>molecules of P₂O₅ to atoms</em>.
There are seven atoms in 1 mol P₂O₅.
∴ 
Answer:


Explanation:
Given



Required
Determine the area
The area of a triangle is :

By substituting values for the x and y coordinates of A, B and C;
We have:

So:
For instance



The area is:





