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allochka39001 [22]

3 years ago

14

Which statement correctly describes protons? They have no charge and are present in the nucleus of an atom. They have a negative

charge and travel around the nucleus of an atom. They have a positive charge and travel around the nucleus of an atom. They have a positive charge and are present in the nucleus of an atom along with the neutrons.

2 answers:

Kamila [148]3 years ago

5 0

AnswerD is the correct answer. for your information, A describes the neutrons and B describes the electrons. C is wrong.

tatiyna3 years ago

5 0

The last sentence is true abt proton

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There are 6 different organisms in the picture above. Organize them into 2 or more groups AND defend your groups by

anyanavicka [17]

Answer:

thay all are different from each other

5 0

3 years ago

At 850K, 65L of gas has a pressure of 450kPa. What is the volume (in liters) if the gas is cooled to 430K and the pressure decre

Novosadov [1.4K]

Answer:

V₂ = 45.53 L

Explanation:

Given data:

Initial temperature = 850 K

Initial volume = 65 L

Initial pressure = 450 KPa

Final temperature = 430 K

Final pressure = 325 KPa

Final volume = ?

Solution:

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂

V₂ = 450 KPa× 65 L × 430 K / 850 K × 325KPa

V₂ = 12577500 KPa .L. K / 276250 K. KPa

V₂ = 45.53 L

8 0

3 years ago

Which explanation of the solar system best fits the observations of the planets and how they orbit the sun?

Svetllana [295]

<span>The sun and planets formed from a collapsing spinning cloud of gas and dust.</span>

6 0

3 years ago

Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

Pani-rosa [81]

The question is incomplete, here is the complete question:

Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

Atmospheric Gas Mole Fraction kH mol/(L*atm)

$N_2$ $7.81\times 10^{-1}$ $6.70\times 10^{-4}$

$O_2$ $2.10\times 10^{-1}$ $1.30\times 10^{-3}$

Ar $9.34\times 10^{-3}$ $1.40\times 10^{-3}$

$CO_2$ $3.33\times 10^{-4}$ $3.50\times 10^{-2}$

$CH_4$ $2.00\times 10^{-6}$ $1.40\times 10^{-3}$

$H_2$ $5.00\times 10^{-7}$ $7.80\times 10^{-4}$

<u>Answer:</u> The solubility of hydrogen gas in water at given atmospheric pressure is $1.48\times 10^{-10}M$

<u>Explanation:</u>

To calculate the partial pressure of hydrogen gas, we use the equation given by Raoult's law, which is:

$p_{\text{hydrogen gas}}=p_T\times \chi_{\text{hydrogen gas}}$

where,

$p_A$ = partial pressure of hydrogen gas = ?

$p_T$ = total pressure = 0.380 atm

$\chi_A$ = mole fraction of hydrogen gas = $5.00\times 10^{-7}$

Putting values in above equation, we get:

$p_{\text{hydrogen gas}}=0.380\times 5.00\times 10^{-7}\\\\p_{\text{hydrogen gas}}=1.9\times 10^{-7}atm$

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{H_2}=K_H\times p_{H_2}$

where,

$K_H$ = Henry's constant = $7.80\times 10^{-4}mol/L.atm$

$p_{H_2}$ = partial pressure of hydrogen gas = $1.9\times 10^{-7}atm$

Putting values in above equation, we get:

$C_{H_2}=7.80\times 10^{-4}mol/L.atm\times 1.9\times 10^{-7}atm\\\\C_{CO_2}=1.48\times 10^{-10}M$

Hence, the solubility of hydrogen gas in water at given atmospheric pressure is $1.48\times 10^{-10}M$

4 0

3 years ago

2 Na + 1 Cl2 → 2 Naci<br> How many grams of NaCl are created from 23,2 grams Cl2?

evablogger [386]

37 grams of NaCl (when I mean equivalent I mean the ratio of the equation is 1:2 for moles or Cl2 and NaCl

3 0

2 years ago