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3 years ago

14

What is the overall charge of an ion that has 12 protons, 10 electrons, and 14 neutrons?

1 answer:

kakasveta [241]3 years ago

6 0

The charge of the ion would be +2, because there are 2 more protons than there are electrons. The neutrons don't matter because they have a neutral charge, meaning they are neither positive nor negative.

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A body was found with no evidence of rigor.

musickatia [10]

The person has just died or has been dead for 36-48 hours 2. A body was found exhibiting rigor throughout the entire body. ... The body has been dead for about 6-8 hours because rigor mortis takes 12 hours to compute so it must be before 12 hours but over 6.

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3 years ago

How many atoms are in 12 moles of sodium?

yawa3891 [41]

Answer: There are 1.20 x 1024 atoms of sodium in 2 moles

Explanation:

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3 years ago

Urea (CH4N2O) is a common fertilizer that can be synthesized by the reaction of ammonia (NH3) with carbon dioxide as follows: 2N

yuradex [85]

Answer:

<em>The limiting reactant is </em><u><em>Carbon dioxide, </em></u> $CO_{2}$

Explanation:

The balanced reaction equation is:

$2NH_{3} + CO_{2}$ → $CH_{4} N_{2} O + H_{2} O$

The mole ratio of ammonia to carbon dioxide is 2:1

142100/17g = 8358.8 mol of NH3

211400/44g = 4, 804.5 mole of CO2

Now:

4,804.5 mol of CO2 × $\frac{2 mol NH_{3} }{1 molCO_{2} }$ = 9,609 mol of NH3 present

8,358.8 mole of NH3 × $\frac{1 moleCO_{2} }{2moles NH_{3} }$ = 4,179.4 mol of CO2 present

<em>NH3 needs 8, 358.8 moles but had 9, 609 moles⇒ excess reactant</em>

<em>CO2 needs 4, 804,5 mol but had 4, 179.4 moles⇒ limiting reactant (used up completely)</em>

<u>The limiting reactant is carbon dioxide, CO2.</u>

8 0

4 years ago

I need help with these 2 problems ASAP please.

Leya [2.2K]

I think the answer for the first question is sickle-cell anemia and second question is phenylketonuria (PKU)

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3 years ago

Read 2 more answers

How many grams of NaOH are produced from 2.1g of Na2O?<br> Na2O + H20 --> 2NaOH

Lerok [7]

Answer:

2.72g

Explanation:

The balanced equation of this reaction is given as follows:

Na2O + H20 --> 2NaOH

Based on this balanced equation, 1 mole of Na2O will produce 2 moles of NaOH.

First, we need to convert mass of Na2O into moles by using the formula;

mole = mass/molar mass

Molar mass of Na2O = 23(2) + 16

= 46 + 16

= 62g/mol

mole = 2.1g/62g/mol

mole of Na2O = 0.034mol

Hence, if 1 mole of Na2O will produce 2 moles of NaOH.

Then, 0.034mol of Na2O will produce (0.034 × 2) = 0.068mol of NaOH.

To convert mole of NaOH to mass, we use;

mole = mass/molar mass

Molar mass of NaOH = 23 + 16 + 1 = 40g/mol

0.068 = mass/40

mass of NaOH produced = 2.72g.

4 0

3 years ago