chlorine has the atomic mass of 35.5 and is a non metal in the halogen family
A. The negative ionic radius is larger than the neutral atomic radius.
One half-life: 5 grams
Two half-lives: 2.5 grams
<u>Given:</u>
Mass of solvent water = 4.50 kg
Freezing point of the solution = -11 C
Freezing point depression constant = 1.86 C/m
<u>To determine:</u>
Moles of methanol to be added
<u>Explanation:</u>
The freezing point depression ΔTf is related to the molality m through the constant kf, as follows:
ΔTf = kf*m
where ΔTf = Freezing point of pure solvent (water) - Freezing pt of solution
ΔTf = 0 C - (-11.0 C) = 11.0 C
m = molality = moles of methanol/kg of water = moles of methanol/4.50 kg
11.0 = 1.86 * moles of methanol/4.50
moles of methanol = 26.613 moles
Ans: Thus around 26.6 moles of methanol should be added to 4.50 kg of water.
Answer:
D. C > B >A
Hope it helps!
Explanation:
From strongest to weakest, the intermolecular forces rank in the following way:
Strongest: Hydrogen bonding. This occurs when compounds contain #"O"-"H"# , #"N"-"H"# , or #"F"-"H"# bonds. ...
Less strong: Dipole-dipole forces. ...
Weakest: London Dispersion Forces.
