We have that the time it will take Jupiter to around the sky is mathematically given as
Psyn=295days
<h3>Time for Jupiter to around the sky</h3>
Question Parameters:
If it takes Jupiter 13 years to orbit the Sun.
Generally, The earth moved a bit further, one Jupiter period ago, This is called synodic period

Psyn=295days
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Answer:
Vf = 73.4 m/s
Explanation:
This is the case of vertical motion where we have to find the final velocity of the penny when it hits the ground. We can use 3rd equation of motion to find the final velocity:
2gh = Vf² - Vi²
where,
g = 9.8 m/s²
h = height = 275 m
Vf = Final Velocity = ?
Vi = Initial Velocity = 0 m/s
Therefore,
2(9.8 m/s²)(275 m) = Vf² - (0 m/s)²
Vf = √5390 m²/s²
<u>Vf = 73.4 m/s</u>
They would have the magnetic parts of the rocks oriented differently. This leaves a trace that allow scientists to find out how often this actually happens (as far as I remember, it's on average once in 800 000 years)
To solve this problem, we use the equation:
<span>d = (v^2 - v0^2) /
2a</span>
where,
d = distance of collapse
v0 = initial velocity = 101 km / h = 28.06 m / s
v = final velocity = 0
a = acceleration = - 300 m / s^2
d = (-28.06 m / s)^2 / (2 * - 300 m / s^2)
<span>d = 1.31 m</span>
Answer:
x = -1.20 m
y = -1.12 m
Explanation:
as we know that four masses and their position is given as
5.0 kg (0, 0)
2.9 kg (0, 3.2)
4 kg (2.5, 0)
8.3 kg (x, y)
As we know that the formula of center of gravity is given as




Similarly for y direction we have



