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Romashka [77]
2 years ago
12

Atoms of which pair of elements will form covalent bonds in a compound? ASAP PLZ

Physics
2 answers:
frez [133]2 years ago
5 0

Answer:

the answer is A........

zubka84 [21]2 years ago
5 0

Answer:B

Explanation:

C and O

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Why are coal,nuclear,oil,and natural gas determined to be non-renewable types of energy resources ​
IrinaVladis [17]

Answer:

Once used as a energy source they cannot be charged/used again.

Explanation:

7 0
3 years ago
A small bug walks up a wall 2 m. The bug then walks 2 m down the wall. What is the distance?
gizmo_the_mogwai [7]
4m. The big travels 2m twice
5 0
2 years ago
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If the centripetal and thus frictional force between the tires and the roadbed of a car moving in a circular
erastova [34]

Answer;

D. The car would begin to move in the direction it was headed in a straight line.

Explanation;

-Centripetal force is any net force causing uniform circular motion. The direction of a centripetal force is toward the center of curvature, the same as the direction of centripetal acceleration.

-The centripetal force causing the car to turn in a circular path is due to friction between the tires and the road. A minimum coefficient of friction is needed, or the car will move in a larger-radius curve and leave the roadway.

-Therefore,If the centripetal and thus frictional force between the tires and the roadbed of a car moving in a circular path were reduced then the car would begin to move in the direction it was headed in a straight line.

6 0
3 years ago
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The net horizontal force on a car is 981 N. The car has a mass of 1550 kg and the force is applied when the car has a speed of 2
viktelen [127]

Answer:

Distance, d = 778.05 m                          

Explanation:

Given that,

Force acting on the car, F = 981 N

Mass of the car, m = 1550 kg

Initial speed of the car, v = 25 mi/h = 11.17 m/s

We need to find the distance covered by car if the force continues to be applied to the car. Firstly, lets find the acceleration of the car:

F=ma\\\\a=\dfrac{F}{m}\\\\a=\dfrac{981}{1550}\\\\a=0.632\ m/s^2

Let d is the distance covered by car. Using second equation of motion as :

d=ut+\dfrac{1}{2}at^2\\\\d=11.17\times 35+\dfrac{1}{2}\times 0.632\times (35)^2\\\\d=778.05\ m

So, the car will cover a distance of 778.05 meters.

5 0
3 years ago
Does the planet exert a torque on the meteoroid with respect to the center of mass of the planet? Why or why not?
ra1l [238]

Answer:

yes

Explanation:

because the planet exerts a centripetal force on the meteorold

4 0
3 years ago
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