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3 years ago

Water has physical properties that can be measured and

1 answer:

3 0

Physical properties of water are related to the appearance of water, namely, the color, temperature, turbidity, taste, and odor. ... Turbidity is a measure of the clarity of water. Low-turbidity water is clear, while high turbidity water is cloudy or murky. The unit of measuring turbidity is turbidity

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There are two blocks: one large one initially at rest, and a smaller one, initially moving to the right withsome speed. The smal

KATRIN_1 [288]

Answer:

Explanation:

Let the initial velocity of small block be v .

by applying conservation of momentum we can find velocity of common mass

25 v = 75 V , V is velocity of common mass after collision.

V = v / 3

For reaching the height we shall apply conservation of mechanical energy

1/2 m v² = mgh

1/2 x 75 x V² = 75 x g x 10

V² = 2g x 10

v² / 9 = 2 x 9.8 x 10

v² = 9 x 2 x 9.8 x 10

v = 42 m /s

small block must have velocity of 42 m /s .

Impulse by small block on large block

= change in momentum of large block

= 75 x V

= 75 x 42 / 3

= 1050 Ns.

6 0

3 years ago

NEED ASAP PLEASE !!

Svetllana [295]

The balloon was 30.65 meters above ground.

ANSWER: A

3 0

3 years ago

Read 2 more answers

Jupiter’s Great Red Spot rotates completely every six days. If the spot is circular (not quite true, but a reasonable approximat

artcher [175]

Answer:

$v = 567.2 km/h$

Explanation:

As we know that if Jupiter Rotate one complete rotation then it means that the it will turn by 360 degree angle

so here the distance covered by the point on its surface in one complete rotation is given by

$distance = 2\pi r$

$distance = \pi D$

now we will have the time to complete the rotation given as

$t = 6 days$

$t = 6 (24 h) = 144 h$

now the speed is given by

$speed = \frac{distance}{time}$

$speed = \frac{\pi D}{t}$

$speed = \frac{\pi(26000 km)}{144}$

$v = 567.2 km/h$

5 0

3 years ago

A mass of 10 g of oxygen fill a weighted pistonâ€“cylinder device at 20 kPa and 110Â°C. The device is now cooled until the tempe

mezya [45]

Answer:

The change of the volume of the device during this cooling is $14.3\times10^{-3}\ m^3$

Explanation:

Given that,

Mass of oxygen = 10 g

Pressure = 20 kPa

Initial temperature = 110°C

Final temperature = 0°C

We need to calculate the change of the volume of the device during this cooling

Using formula of change volume

$\Delta V=V_{2}-V_{1}$

$\Delta V=\dfrac{mR}{P}(T_{2}-T_{1})$

Put the value into the formula

$\Delta V=\dfrac{0.3125\times0.0821}{2.0265\times10^{9}}(383-273)$

$\Delta V=14.297\ L$

$\Delta V=14.3\times10^{-3}\ m^3$

Hence, The change of the volume of the device during this cooling is $14.3\times10^{-3}\ m^3$

6 0

3 years ago

For a snowboard jumper in the air, what force or forces will be most important for modeling the motion?

Reptile [31]

Answer: Gravitational force and drag force

Explanation:

For a snowboard jumper in the air, two forces would be acting. One in the downward direction- the gravitational pull and second in the opposite direction to the motion, the drag force due to air. If the snowboard jumper jumps in the air at a certain angle with the horizontal. The forces are written as the sum of vertical and horizontal components. Hence, for the modeling the motion, gravitational force and drag force are important,

4 0

3 years ago