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zmey [24]
4 years ago
8

The speedometer of your car measures average speed?

Physics
1 answer:
Ronch [10]4 years ago
6 0
The speedometer of a car reads instantaneous speed
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A certain car's drive-train produces a force of 5300 N as it accelerates from 0
lakkis [162]

The power is 7.1\cdot 10^4 W

Explanation:

First of all, we need to find the acceleration of the car, which is given by

a=\frac{v-u}{t}

where

v = 60 mph = 26.8 m/s is the final velocity

u = 0 is the initial velocity

t = 10.0 s is the time

Substituting,

a=\frac{26.8-0}{10.0}=2.68 m/s^2

Now we can find the mass of the car by using Newton's second law:

F=ma

where

F = 5300 N is the force applied

m is the mass

a=2.68 m/s^2 is the acceleration

Solving for m,

m=\frac{F}{a}=\frac{5300}{2.68}=1978 kg

Now we can use the work-energy theorem, which states that the work done is equal to the change in kinetic energy of the car, to find the work:

W=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2

And substituting,

W=\frac{1}{2}(1978)(26.8)^2-0=7.10\cdot 10^5 J

Finally, we can find the power output of the car:

P=\frac{W}{t}

where

W is the work

t = 10.0 s is the time elapsed

Substituting,

P=\frac{7.1\cdot 10^5}{10.0}=7.1\cdot 10^4 W

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

4 0
4 years ago
An 80kg parachutist jumps out of an airplane. Neglecting air friction, how fast will he be going after a 10 second free fall?
olganol [36]
If he is jumping you are adding force which means that you will be falling twice as fast
6 0
3 years ago
A constant net force of 345 N is applied to slide a heavy stationary
liubo4ka [24]

Answer:

P = 517.5 [kg*m/s]

Explanation:

We must remember that momentum is defined as the product of force by the time of force duration.

P=F*t

where:

P = momentum [kg*m/s]

F = force [N]

t = time [s]

P=345*1.5\\P=517.5[kg*m/s]

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Cutting and polishing exposed rock
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The magnetic field lines outside a bar magnet
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The lines of magnetic field from a bar magnet form closed lines. By convention, the field direction is taken to be outward from the North pole and in to the South pole of the magnet.
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