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vazorg [7]
3 years ago
10

NEED ASAP PLEASE HELP

Physics
1 answer:
sveta [45]3 years ago
3 0
1. GPE - 40 * 2 * 10 = 800j
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Explain why understanding bonding is important for understanding molecules.
matrenka [14]
Bond<span> polarity is </span>important<span> because it helps to determine the polarity of </span>molecules<span> and hence their physical properties.</span>
6 0
3 years ago
A lamp can work on 50V mains taking 2 amps. What value of resistance must be connected in series with it, so that it can be oper
wolverine [178]
The resistance of the lamp is apparently  50V/2A  =  25 ohms.

When the circuit is fed with more than 50V, we want to add
another resistor in series with the 25-ohm lamp so that the
current through the combination will be 2A.

In order for 200V to cause 2A of current, the total resistance
must be      200V/2A = 100 ohms.

The lamp provides 25 ohms, so we want to add another 75 ohms 
in series with the lamp.  Then the total resistance of the circuit is
(75 + 25) = 100 ohms, and the current is 200V/100 ohms = 2 Amps.

The power delivered by the 200V mains is (200V) x (2A) = 400 watts.

The lamp dissipates ( I² · R ) = (2² · 25 ohms) = 100 watts.

The extra resistor dissipates  ( I² · R) = (2² · 75 ohms) = 300 watts.

Together, they add up to the 400 watts delivered by the mains.

CAUTION:
300 watts is an awful lot of power for a resistor to dissipate !
Those little striped jobbies can't do it. 
It has to be a special 'power resistor'. 
300 watts is even an unusually big power resistor.
If this story actually happened, it would be cheaper, easier,
and safer to get three more of the same kind of lamp, and
connect THOSE in series for 100 ohms.  Then at least the
power would all be going to provide some light, and not just
wasted to heat the room with a big moose resistor that's too
hot to touch.
3 0
3 years ago
g How many diffraction maxima are contained in a region of the Fraunhofer single-slit pattern, subtending an angle of 2.12°, for
lbvjy [14]

Answer:

2

Explanation:

We know that in the Fraunhofer single-slit pattern,

maxima is given by

a\text{sin}\theta=\frac{2N+1}{2}\lambda

Given values

θ=2.12°

slit width a= 0.110 mm.

wavelength λ= 582 nm

Now plugging values to calculate N we get

0.110\times10^{-3}\text{sin}2.12=(\frac{2N+1}{2})582\times10^{-9}

Solving the above equation we get

we N= 2.313≅ 2

4 0
3 years ago
Im back and need help
const2013 [10]

Always here to help. Bring it!!!

7 0
3 years ago
The power in an electric circuit varies inversely with the resistance. If the power is 2,200 watts when the resistance is 25 ohm
valentinak56 [21]

Answer:

The value of resistance when power is 1100 watts = R_{2} = 50 ohms

Explanation:

Power P_{1} = 2200 Watts

Resistance R_{1} = 25 ohms

Power P_{2} = 1100 Watts

Resistance R_{2} = we have to calculate

Given that the power in an electric circuit varies inversely with the resistance

⇒ P ∝ \frac{1}{R}

⇒ \frac{P_{2} }{P_{1} } = \frac{R_{1} }{R_{2} }

⇒ \frac{1100}{2200} = \frac{25}{R_{2} }

⇒ R_{2} = 50 ohms

This is the value of resistance when power is 1100 watts.

6 0
4 years ago
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