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4 years ago

What is the difference between static and Kenetic friction?

1 answer:

3 0

Static friction is the friction between an object at rest and the surface on which it is resting on.

Kinetic friction is the friction between a moving object and the surface on which it moves.

Hopefully you understood and this helps :)

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The storage method used for radioactive wastes generated from fission nuclear reactors must be designed to last for how long?

Phantasy [73]

Answer:

The storage method is originally designed to last years. The exact amount of time comes down to what type of waste it is.

4 0

3 years ago

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What is the orbital period in years of a planet with a semi major axis of 35 au

mezya [45]

Answer:

Orbital period of the planet will be 207.06 year

Explanation:

We have given the planet have the semi major axis as 35 au

We have to find the orbital period of the planet

From Keplar's third law there is relation between the orbital period and semi major axis which is t $T^2=R^3$

So $T^2=35^3$

$T^2=42875$

$T=207.06year$

So orbital period of the planet will be 207.06 year

6 0

3 years ago

A person travels by car from one city to an-

Mademuasel [1]

<h2>Answer:</h2>

<h2>Explanation:</h2>

First, let's refer to the distance formula:

$d=v*t$ , where d is distance, v is velocity or speed and t is time.

Now, let's find the distance covered by each individual speed that the car had:

<h3>1. Speed 1.</h3>

In order to use the formula, we need to convert minutes into hours since the speed is given in km/h.

21.1 min/60= 0.35 h.

Now, apply the distance formula.

d=(0.35h)*(86.8km/h)= 30.38 km.

<h3>2. Speed 2.</h3>

Convert minutes to hours again and do the same calculations.

10.6min/60=0.18h

d=(0.18h)*(106km/h)= 19.08 km.

<h3>3. Speed 3.</h3>

36.5min/60= 0.61h

d=(0.61h)*(30.9km/h)= 18.85 km.

<h3>4. Obtain the total distance.</h3>

The total distance must be given by the addition of all individual distances traveled by the car on each speed:

Total distance= 30.38 km + 19.08 km + 18.85 km= 68.31 km.

5 0

2 years ago

calculate the diameter of a silver wire of length 75cm , which is extended by 1.85mm when a 10kg mass is suspended from it's end

sdas [7]

Answer: $0.8\ mm$

Explanation:

Given

length of wire $l=75\ cm$

change in length $\Delta l=1.85\ mm$

mass of wire $m=10\ kg$

Young's modulus for silver $E=7.9\times 10^{10}\ N/m^2$

load on wire $F=mg$

$F=10\times 9.8=98\ kg$

change in length is given by

$\Delta l=\dfrac{Pl}{AE}$

Where A=area of cross-section

$A=\dfrac{Pl}{\Delta lE}$

$A=\dfrac{98\times 0.75}{1.85\times 10^{-3}\times 7.9\times 10^{10}}$

$A=\dfrac{73.5}{14.615\times 10^{7}}$

$A=5.029\times 10^{-7}\ m^2$

also wire is the shape of cylinder so cross-section is given by

$A=\dfrac{\pi d^2}{4}=5.029\times 10^{-7}\ m^2$

$\Rightarrow d^2=\dfrac{5.029\times 10^{-7}\times 4}{\pi }$

$\Rightarrow d^2=64.02\times 10^{-8}$

$\Rightarrow d=8\times 10^{-4}\ m$

$\Rightarrow d=0.8\ mm$

4 0

3 years ago

In this experiment, you will use a natural indicator to indirectly determine the H+ concentration of some common household solut

Vlad1618 [11]

Some of the scientific questions that may be answered through the experiment are:

(1) What are the physical changes that may occur in the solution or the indicator when added with acidic/basic solution?

(2) How much of the indicator is needed in order to bring about a significant physical change in the solution to identify its H+ concentration?

7 0

3 years ago

Read 2 more answers