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Arisa [49]
3 years ago
6

Acids naturally present in food are safe to eat because they usually are

Chemistry
2 answers:
Artemon [7]3 years ago
8 0

Answer:

This question is not complete but the completed question is below

Acids naturally present in food are safe to eat because they usually are

A. Weak

B. concentrated

C. dilute

D. strong

The correct option is A.

Explanation:

Acids that are naturally found in food are organic acids. Organic acids are generally known to be weak acids. An acid is a substance that produces hydrogen ion or hydroxonium ion when dissolved in water.

A weak acid however ionizes partially (not releasing all its possible hydrogen ions) in water. Weak acids have pH that are close to neutral (pH 7) and hence are safe for consumption.

tangare [24]3 years ago
7 0
A.Weak

B.concentrated

C.dilute

D.strong



Answer: A - Weak

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II. Ionic Equations
mario62 [17]

Answer:

Complete ionic: \begin{aligned}& \rm 2\, Ag^{+}\, (aq) + 2\, {NO_3}^{-} \, (aq) + Ca^{2+}\, (aq) + 2\, Cl^{-}\, (aq) \\ & \rm \to 2\, AgCl\, (s) + Ca^{2+}\, (aq) + 2\, {NO_3}^{-}\, (aq)\end{aligned}.

Net ionic: \begin{aligned}& \rm Ag^{+}\, (aq) + Cl^{-}\, (aq) \to AgCl\, (s)\end{aligned}.

Explanation:

Start by identifying species that exist as ions. In general, such species include:

  • Soluble salts.
  • Strong acids and strong bases.

All four species in this particular question are salts. However, only three of them are generally soluble in water: \rm AgNO_3, \rm CaCl_2, and \rm Ca(NO_3)_2. These three salts will exist as ions:

  • Each \rm AgNO_3\, (aq) formula unit will exist as one \rm Ag^{+} ion and one \rm {NO_3}^{-} ion.
  • Each \rm CaCl_2 formula unit will exist as one \rm Ca^{2+} ion and two \rm Cl^{-} ions (note the subscript in the formula \rm CaCl_2\!.)
  • Each \rm Ca(NO_3)_2 formula unit will exist as one \rm Ca^{2+} and two \rm {NO_3}^{-} ions.

On the other hand, \rm AgCl is generally insoluble in water. This salt will not form ions.

Rewrite the original chemical equation to get the corresponding ionic equation. In this question, rewrite \rm AgNO_3, \rm CaCl_2, and \rm Ca(NO_3)_2 (three soluble salts) as the corresponding ions.

Pay attention to the coefficient of each species. For example, indeed each \rm AgNO_3\, (aq) formula unit will exist as only one \rm Ag^{+} ion and one \rm {NO_3}^{-} ion. However, because the coefficient of \rm AgNO_3\, (aq)\! in the original equation is two, \!\rm AgNO_3\, (aq) alone should correspond to two \rm Ag^{+}\! ions and two \rm {NO_3}^{-}\! ions.

Do not rewrite the salt \rm AgCl because it is insoluble.

\begin{aligned}& \rm 2\, Ag^{+}\, (aq) + 2\, {NO_3}^{-} \, (aq) + Ca^{2+}\, (aq) + 2\, Cl^{-}\, (aq) \\ & \rm \to 2\, AgCl\, (s) + Ca^{2+}\, (aq) + 2\, {NO_3}^{-}\, (aq)\end{aligned}.

Eliminate ions that are present on both sides of this ionic equation. In this question, such ions include one unit of \rm Ca^{2+} and two units of \rm {NO_3}^{-}. Doing so will give:

\begin{aligned}& \rm 2\, Ag^{+}\, (aq) + 2\, Cl^{-}\, (aq) \to 2\, AgCl\, (s)\end{aligned}.

Simplify the coefficients:

\begin{aligned}& \rm Ag^{+}\, (aq) + Cl^{-}\, (aq) \to AgCl\, (s)\end{aligned}.

7 0
2 years ago
Silvers symbol on the periodic table of the elements is Ag. what else is true of silver?
pishuonlain [190]
The answer should be D hope this helps
4 0
3 years ago
Please help, this assignment is to hard for me. :(
iren [92.7K]

Answer:

603000 J

Explanation:

The following data were obtained from the question:

Energy required (Q) =...?

Mass (M) = 10000 g

Specific heat capacity (C) = 2.01 J/g°C

Overheating temperature (T2) = 121°C

Working temperature (T1) = 91°C

Change in temperature (ΔT) =.?

Change in temperature (ΔT) =T2 – T1

Change in temperature (ΔT) = 121 – 91

Change in temperature (ΔT) = 30°C

Finally, we shall determine the energe required to overheat the car as follow:

Q = MCΔT

Q = 10000 × 2.01 × 30

Q = 603000 J

Therefore, 603000 J of energy is required to overheat the car.

7 0
3 years ago
What is the pH of a solution that has a hydroxide ion concentration of 1.0×10−9 M?
bogdanovich [222]

Answer:

\boxed{\text{pH = 5.00}}

Explanation:

Step 1. Calculate the pOH

pOH =-log[OH⁻]

pOH =-log(1.0 × 10⁻⁹)

pOH = 9.00

Step 2. Calculate the pH

pH + pOH = 14.00

pH + 9.00 = 14.00

\boxed{\textbf{pH = 5.00}}

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3 years ago
How many atoms will be in a 0.010 gram sample of aluminum
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Um let me think ummm dang hold on bro i will be right back ok 
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